a2 + b2 = c2 a2 = c2 - b2 a = sqrt(c2 - b2) ==================no +/- square root as a negative length makes no sense in a right triangle
a2+b2=c2
A2+B2= c2
a2+b2=c2
l a2 b2 is c2!!Its completely norma
They are: a2+b2 = c2 c2-a2 = b2 c2-b2 = a2
Yes! Since it has un-paired electrons: ) Actually C2 isn't paramagnetic. There's certain type of diagram how to determine whether molecule is paramagnetic or not. And C2 isn't. Instead C2(2+) would be paramagnetic.
If you are talking about a2+b2=c2 then that is Pythagorean theorem.
a2
C2=A2+B2 Therefore to find B2: B2=C2-A2
a2 + b2 = c2 a2 = c2 - b2 a = sqrt(c2 - b2) ==================no +/- square root as a negative length makes no sense in a right triangle
The bond order of B2 is 1.
yes c2=a2+b2
sorry this is only ibong pipit#1-c2 e g c2-g e a2-f d-g f e d c-e g c2-g e-g g#2-e ege ege egfg a2,,,-f fa2f fa2f fa2ga 2b2,,,,#3-c2 d2 d2 e2 d2,,, d2 e2 d2 c2 b2 c2 c2 d2 c2c2 d2 c2 b2 a2 g-(d2 e2 f2 g2-d2 e2 f2 g2-d2 e2 f2 g2 e2,,,,)repeat # 3 (a2 b2 c2 a2 b2 c2 a2 b2-e2 e2 e2-d2 c2 b2 a2 g a2 b2 c2repeat #1
Assuming that you are talking about a right triangle. a2 + b2 = c2 Solve for a a = square root of c2-b2
sorry this is only ibong pipit#1-c2 e g c2-g e a2-f d-g f e d c-e g c2-g e-g g#2-e ege ege egfg a2,,,-f fa2f fa2f fa2ga 2b2,,,,#3-c2 d2 d2 e2 d2,,, d2 e2 d2 c2 b2 c2 c2 d2 c2c2 d2 c2 b2 a2 g-(d2 e2 f2 g2-d2 e2 f2 g2-d2 e2 f2 g2 e2,,,,)repeat # 3 (a2 b2 c2 a2 b2 c2 a2 b2-e2 e2 e2-d2 c2 b2 a2 g a2 b2 c2repeat #1
a2 + b2 = C2