my laptop sucks, otherwise I would have answered to this question.
Use Avogadro's number. 2 mole Fe(3+) ( 6.022 X 10^23/1 mole Fe(3+) ) = 1.20 X 10^24 ions of Fe(3+)
Iron (Fe)
Yes
combination
CuSO4 (aq) + Fe (s) -> FeSO4 (aq) + Cu (s)
Fe 2+ is Ferrous Fe 3+ is Ferric
In a neutral compound, the ratio of Fe³⁺ ions to O²⁻ ions is 2:3. This is because Fe³⁺ has a +3 charge, while O²⁻ has a -2 charge. To balance the charges, two Fe³⁺ ions contribute a total charge of +6, which is balanced by three O²⁻ ions contributing a total charge of -6. Thus, the formula of the neutral compound would be Fe₂O₃.
O does not exist by itself. The balanced equation would be 4Fe + 3O2 --> 2Fe2O3
Use Avogadro's number. 2 mole Fe(3+) ( 6.022 X 10^23/1 mole Fe(3+) ) = 1.20 X 10^24 ions of Fe(3+)
Fe + 3AgNO3 ==> Fe(NO3)3 plus 3Ag The oxidation number of Ag in AgNO3 (on the left side) is 1+ and in Ag (on the right side), it is zero. Thus, in this reaction, silver (Ag) has been reduced.
H3PO4 is added to Mohr's salt (ammonium iron(II) sulfate) to prevent oxidation of Fe²⁺ ions to Fe³⁺ ions during permanganate titrations. This reaction interferes with the accurate determination of oxidizable substances and is minimized by the presence of H3PO4, which stabilizes Fe²⁺ ions.
Cr and Fe have four unpaired electrons in their 2 plus ions.
When freshly precipitated Fe(OH)3 is shaken with a dilute solution of FeCl3, the hydroxide can dissolve back into the solution due to the formation of soluble complexes. This occurs because FeCl3 can provide additional iron ions (Fe³⁺), which can interact with the hydroxide ions (OH⁻) from Fe(OH)3, leading to the dissolution of the precipitate and the formation of soluble iron species. The process can also lead to the formation of a colloidal suspension if the conditions favor it.
two elements with ions with a 2 plus charge are Sulfurand Oxygen
When iron is immersed in an acidic solution, it can react with the hydrogen ions from the acid to form ferrous ions (Fe2+). These ferrous ions can then react with hydroxide ions (OH-) in the solution to form iron(II) hydroxide (Fe(OH)2), which is a metallic hydroxide compound.
The oxidation half-reaction for the given equation is: Fe → Fe2+ + 2e-. This represents the loss of electrons from iron (Fe) to form iron ions (Fe2+).
No, it forms positive ions.