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MaxineMirrors are painted red on the backside to prevent the formation of a secondary image. When light passes through the glass of the mirror and reflects off the red paint, it gets absorbed rather than reflecting back through the glass. This absorption helps to eliminate the formation of a faint secondary image that can sometimes occur with regular mirrors.
Well, isn't that a happy little question! Mirrors are painted red on the backside to protect the reflective coating from damage and scratches. The red paint acts as a barrier, ensuring that the mirror stays shiny and clear for a long time. Just like adding a touch of crimson to a painting, it's all about preserving and enhancing the beauty of the mirror.
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A cube is painted red and cut into 64 cubes how many have 6 red faces 5 red faces 4 red faces 3 red faces 2 red faces 1 red face?
There would be 8 will 3 faces painted red, 24 with 2 faces painted red, 24 with 1 face painted red, and 8 that have no faces painted red.
A cube is painted red and then cut into 216 little cubes all of the same size how many of the little cubes have 6 red faces 5 red faces 4 red faces 3 red faces 2 red faces 1 red face?
Draw a three dimensional cube, showing three faces. Divide each face into 6 x 6 =36 squares, representing the faces of the little cubes. Then by inspection it is obvious that no little cube can have more then three painted faces and they will be at the eight corners. Only the edge cubes (not counting the corners) can have two painted faces and there are 48 of then. Finally, only the inner cubes on the surfaces will have one painted face and there are 96 of them. The other 64 cubes are in the inner core and will have no painted surfaces. SO: 6 = 0 ; 5 = 0; 4 =0 ; 3 = 8 ; 2 = 48 ; 1 = 96 . uuuuuu.....
Where you find exergue?
On the backside of a medal.
A cube of side 8 cm was painted red yellow and green on opposite faces it was cut into cubical boxes each of size 2cm ans the foll- no of cubes with 1 2 and 3 sides painted?
The colors don't matter. And I'm having to assume from your description that you mean that the smaller cubes have sides of length 2 cm long. Thus, there are 64 cubes. 8 have three sides painted. 24 have two sides painted. 24 have one side painted. 8 have no sides painted.
A cube is painted red and then cut into 64 little cubes all of the same size how many of the little cubes have 6 red faces 5 red faces 4 red faces 3 red faces 2 red faces 1 red face?
This is kind of neat. I drew a three dimensional cube. Then divided the faces into 16 squares per face. Then started counting which of those little cubes would have a painted face. I get: 1 red face - 24 cubes 2 red faces - 24 cubes 3 red faces - 8 cubes 4, 5, & 6 red faces - 0 cubes
