The number of partial products in multiplication depends on the number of digits in the factors being multiplied. In 1(a), if there are three digits in one factor, each digit contributes a partial product when multiplied by the other factor, resulting in three partial products. In 1(b), if one factor has two digits, it will produce only two partial products corresponding to its two digits. Thus, the difference in the number of partial products reflects the number of digits in the factors being multiplied.
There are three feet in 1 yard.
10
1000
250mg
14
1
10
16
48 tsp
100 years
no 8 pints
31,556,926 seconds.