They are 391 plus 392 = 783
If x is even, then x+1 is odd. Try this out with a few numbers, to get a "feel" for the situation.
x+3 and x+4 would be consecutive integers.
No. The sum of four consecutive integers is two odd numbers plus two even numbers which is an even number. 2001 is an odd number, therefore it cannot be the sum of four consecutive numbers.
10+(X)+(X+1)=196 10+2X+1=196 11+2X=196 2X=185 X=92.5 Therefore, ten plus the sum of two consecutive integers can not be even.
They are 391 plus 392 = 783
If x is even, then x+1 is odd. Try this out with a few numbers, to get a "feel" for the situation.
x+3 and x+4 would be consecutive integers.
No. The sum of four consecutive integers is two odd numbers plus two even numbers which is an even number. 2001 is an odd number, therefore it cannot be the sum of four consecutive numbers.
10+(X)+(X+1)=196 10+2X+1=196 11+2X=196 2X=185 X=92.5 Therefore, ten plus the sum of two consecutive integers can not be even.
63
+/- 11
Find two consecuitive integers whose sum is 89. To solve this problem, let x be the smaller of these integers. What is the larger of these two consecutive integers? In terms of x, write a formula that represents the sum of these two consecutive integers.
n + n+1 + n + 2 = 3n+3 = 3(n+1)
addition a + b
Actually the problem does not have a solution with the constraint that the two numbers are consecutive integers. With consecutive integers, one of the integers will be odd and the other one even. An even plus an odd always equals an odd, and you want them to add up to 56, which is an even number. 27.5 + 28.5= 56. steps shown below: x+ (x+1)=56 2x+1 = 56 2x= 56-1 2x= 55 x=55/2 x=27.5 second number is x +1= 27.5+1= 28.5
It cannot be done. The basic rules of math. odd integer plus odd integer = even integer. odd integer plus even integer = odd integer. Always. odd integer plus odd integer plus odd integer = odd integer. Always.