Consider the square ABCD whose diagonals, AC and BD, meet at X.AB is parallel to DC and AC intercepts them. Therefore <BAX = <DCX.
AB is parallel to DC and BD intercepts them. Therefore <ABX = <CDX.
AB = CD.
Therefore triangle ABX is congruent to triangle CDX (SAS).
So AX = XC ie X is the midpoint of AC and BX = XB ie X is the midpoint of BD.
ie the diagonals bisect each other.
squares
The diagonals of a square bisect each other at 90 degrees
Yes. Because the diagonals are perpendicular to each other and intersect at their midpoints, they bisect each other.
No, the diagonals of a trapezoid do not necessarily bisect each other. Only in an isosceles trapezoid, where the two non-parallel sides are congruent, will the diagonals bisect each other. In a general trapezoid, the diagonals do not bisect each other.
Square, rhombus and a kite have diagonals that bisect each other at 90 degrees
squares
name 4 diagonals that bisect each other
Yes, the diagonals of a parallelogram bisect each other.
The diagonals of a square (which always bisect each other) are the same length.
The diagonals of a square bisect each other at 90 degrees
Yes the diagonals of a kite bisect each other at 90 degrees.
Not necessarily - the diagonals of a rhombus bisect each other (they are perpendicular bisectors of each other), but are not equal.
Yes. Because the diagonals are perpendicular to each other and intersect at their midpoints, they bisect each other.
An isosceles trapezoid, or any trapezoid, does not have diagonals that bisect each other.
No, the diagonals of a trapezoid do not necessarily bisect each other. Only in an isosceles trapezoid, where the two non-parallel sides are congruent, will the diagonals bisect each other. In a general trapezoid, the diagonals do not bisect each other.
Square, rhombus and a kite have diagonals that bisect each other at 90 degrees
A circle!! * * * * * Wrong: the diagonals of a circle DO bisect each other. A triangle is a possible answer.