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To find the values of ( n ) for which the product ( 3n ) is less than 50, we can set up the inequality ( 3n < 50 ). Dividing both sides by 3 gives ( n < \frac{50}{3} ), which simplifies to ( n < 16.67 ). Therefore, the integer values of ( n ) that satisfy this inequality are ( n = 0, 1, 2, \ldots, 16 ).
What else can I help you with?
For what values of n will the product 3n be less than a 50?
3n < 50 if 3n/3 < 50/3 that is, if n < 50/3 = 162/3.
Twelve less than the product of three and a number?
3n - 12.
What is 5 less than the product of a number and 3 as an expression?
It is 3n - 5.
What is the link between the product of any four consecutive positive integers and some square numbers?
The product of four consecutive integers is always one less than a perfect square. The product of four consecutive integers starting with n will be one less than the square of n2 + 3n + 1
The product of four consective integers is one less than a perfect square?
Suppose the smallest of the integers is n. Then the product of the four consecutive integers is n*(n+1)*(n+2)*(n+3) =(n2+3n)(n2+3n+2) = n4+6n3+11n2+6n So product +1 = n4+6n3+11n2+6n+1 which can be factorised as follows: n4+3n3+n2 +3n3+9n2+3n + n2+3n+1 =[n2+3n+1]2 Thus, one more that the product of four consecutive integers is a perfect square.
For what values of n will the product 3n be less than a 50?
3n < 50 if 3n/3 < 50/3 that is, if n < 50/3 = 162/3.
Twelve less than the product of three and a number?
3n - 12.
What is 5 less than the product of a number and 3 as an expression?
It is 3n - 5.
What is the link between the product of any four consecutive positive integers and some square numbers?
The product of four consecutive integers is always one less than a perfect square. The product of four consecutive integers starting with n will be one less than the square of n2 + 3n + 1
The product of four consective integers is one less than a perfect square?
Suppose the smallest of the integers is n. Then the product of the four consecutive integers is n*(n+1)*(n+2)*(n+3) =(n2+3n)(n2+3n+2) = n4+6n3+11n2+6n So product +1 = n4+6n3+11n2+6n+1 which can be factorised as follows: n4+3n3+n2 +3n3+9n2+3n + n2+3n+1 =[n2+3n+1]2 Thus, one more that the product of four consecutive integers is a perfect square.
Eight less than three times a number?
3n>8
Eight less than 4 times a number is the same as 4 more than 3 times the number what is the number?
4n = 3n + 44n - 3n = 3n - 3n + 4n = 4check:4n = 3n + 44(4) =? 3(4) + 416 =? 12 + 416 = 16 True
The product of a number and 3 is 6?
6=3n or 3n=6
The product of a number and 3?
3n
What is the algebraic expression for Nine less than three times a number?
3n-9
How do you put nine less than three fourths of a number?
3n/4 - 9
What is the expression for 22 less than triple a number?
3n - 22
