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How you find the solution of a quadratic equation by graphing its quadratic equation?
When you graph the quadratic equation, you have three possibilities... 1. The graph touches x-axis once. Then that quadratic equation only has one solution and you find it by finding the x-intercept. 2. The graph touches x-axis twice. Then that quadratic equation has two solutions and you also find it by finding the x-intercept 3. The graph doesn't touch the x-axis at all. Then that quadratic equation has no solutions. If you really want to find the solutions, you'll have to go to imaginary solutions, where the solutions include negative square roots.
What are you finding when you solve a quadratic equation?
You are finding the roots or solutions. These are the values of the variable such that the quadratic equation is true. In graphical form, they are the values of the x-coordinates where the graph intersects the x-axis.
What are the advantage and disadvantage of using factoring in finding solutions in quadratic equation?
ambot cniu nmang kot gnie kmu. . . . . . . . .
What is the solving for the roots of quadratic equation?
It is finding the values of the variable that make the quadratic equation true.
Can someone show you the steps to finding the real roots of x4-9x2 plus 20?
Replace y = x2, and use the quadratic formula to solve for y. This should give you two solutions for y. Then replace back, and solve each of the solutions for y, to get two solutions each for x.
Why do you use square roots to solve quadratic equations?
Because it's part of the quadratic equation formula in finding the roots of a quadratic equation.
How you find the solution of a quadratic equation by graphing its quadratic equation?
When you graph the quadratic equation, you have three possibilities... 1. The graph touches x-axis once. Then that quadratic equation only has one solution and you find it by finding the x-intercept. 2. The graph touches x-axis twice. Then that quadratic equation has two solutions and you also find it by finding the x-intercept 3. The graph doesn't touch the x-axis at all. Then that quadratic equation has no solutions. If you really want to find the solutions, you'll have to go to imaginary solutions, where the solutions include negative square roots.
What are you finding when you solve a quadratic equation?
You are finding the roots or solutions. These are the values of the variable such that the quadratic equation is true. In graphical form, they are the values of the x-coordinates where the graph intersects the x-axis.
What are the advantage and disadvantage of using factoring in finding solutions in quadratic equation?
ambot cniu nmang kot gnie kmu. . . . . . . . .
How do you solve for the point of intersection?
Finding the point of intersection using graphs or geometry is the same as finding the algebraic solutions to the corresponding simultaneous equations.
What is the difference between quadratic function and quadratic formula?
A quadratic function is a function where a variable is raised to the second degree (2). Examples would be x2, or for more complexity, 2x2+4x+16. The quadratic formula is a way of finding the roots of a quadratic function, or where the parabola crosses the x-axis. There are many ways of finding roots, but the quadratic formula will always work for any quadratic function. In the form ax2+bx+c, the Quadratic Formula looks like this: x=-b±√b2-4ac _________ 2a The plus-minus means that there can 2 solutions.
What is algebra1?
Algebra I is based on the basic principles of arithmetic, but also adds symbols, such as letters. Solving and finding solutions for equations are common tasks in Algebra I.
How do you solve quadratic equations by finding square roots?
you use difference of squaresex. X^2-4 can be factored out to (x+2)(x-2)you now have the zeros in your equation much easier
What is the solving for the roots of quadratic equation?
It is finding the values of the variable that make the quadratic equation true.
Finding equations of lines as solutions?
find equation of the line. write equation in slope intercept form. (5,5) parallel line (3,13) and (12,13)
Is finding a substitute a good option for this situation?
Yes, finding a substitute is a good option for this situation.
Can someone show you the steps to finding the real roots of x4-9x2 plus 20?
Replace y = x2, and use the quadratic formula to solve for y. This should give you two solutions for y. Then replace back, and solve each of the solutions for y, to get two solutions each for x.
