That is something that is specific to the method that you are being taught to use for the conversion. There are many methods which are mathematically equivalent but which require different conventions about how and where various intermediate results should be written. I, for one, have never written remainders from bottom to top.
To convert the decimal number 23 into binary, you can divide the number by 2 and record the remainders. Starting with 23, dividing by 2 gives a quotient of 11 and a remainder of 1. Repeating this process results in the remainders: 1, 1, 1, 0, 1. Reading the remainders from bottom to top, 23 in binary is represented as 10111.
The number 51 in binary is represented as 110011. This conversion is achieved by dividing the number by 2 and recording the remainders, which results in the binary digits when read from bottom to top.
It isn't particularly difficult. Just use repeated divisions by 2; the remainders of each division give you the binary digit (in inverse order). Example: Convert 6 to binary. Dividing successively by 2 gives you: 6 / 2 = 3 r 0 3 / 2 = 1 r 1 1 / 2 = 0 r 1 Please note that you must continue until the result of the final division is equal to zero! The answer is 110 (the remainders, read from bottom to top). The above assumes a whole number; if you have decimals, additional calculations are required.
1Set up the problem. For this example, let's convert the decimal number 15610 to binary. Write the decimal number as the dividend inside an upside-down "long division" symbol. Write the base of the destination system (in our case, "2" for binary) as the divisor outside the curve of the division symbol.This method is much easier to understand when visualized on paper, and is much easier for beginners, as it relies only on division by two.To avoid confusion before and after conversion, write the number of the base system that you are working with as a subscript of each number. In this case, the decimal number will have a subscript of 10 and the binary equivalent will have a subscript of 2.2 Divide. Write the integer answer (quotient) under the long division symbol, and write the remainder (0 or 1) to the right of the dividend.[2]Since we are dividing by 2, when the dividend is even the binary remainder will be 0, and when the dividend is odd the binary remainder will be 1.3 Continue to divide until you reach 0. Continue downwards, dividing each new quotient by two and writing the remainders to the right of each dividend. Stop when the quotient is 0.4Write out the new, binary number. Starting with the bottom remainder, read the sequence of remainders upwards to the top. For this example, you should have 10011100. This is the binary equivalent of the decimal number 156. Or, written with base subscripts: 15610 = 100111002This method can be modified to convert from decimal to any base. The divisor is 2 because the desired destination is base 2 (binary). If the desired destination is a different base, replace the 2 in the method with the desired base. For example, if the desired destination is base 9, replace the 2 with 9. The final result will then be in the desired base.
The dividend is the numerator and the divisor is the denominator. Basically, you divide the top number (numerator) by the bottom number (denominator).
The binary number for 25 is 11001. This is because binary is a base-2 number system, meaning each digit can only be 0 or 1. To convert the decimal number 25 to binary, you divide 25 by 2 repeatedly, noting the remainders from each division. Reading the remainders from bottom to top gives you the binary equivalent.
Repeatedly divide by 2. The remainders - in reverse order - form the binary number. You must continue dividing until the result of the division is zero. Example: Convert 11(decimal) to binary. 11 / 2 = 5 r 1 5 / 2 = 2 r 1 2 / 2 = 1 r 0 1 / 2 = 0 r 1. Now list the remainders from bottom to top: 1011. This is the binary representation of eleven.
To convert the decimal number 23 into binary, you can divide the number by 2 and record the remainders. Starting with 23, dividing by 2 gives a quotient of 11 and a remainder of 1. Repeating this process results in the remainders: 1, 1, 1, 0, 1. Reading the remainders from bottom to top, 23 in binary is represented as 10111.
Divide by the number repeatedly by two (until it is zero) and collect the remainders. For example: 13 / 2 = 6 Remainder 1 6 / 2 = 3 Remainder 0 3 / 2 = 1 Remainder 1 1 / 2 = 0 Remainder 1 Reading remainders from bottom yields: 1101
To convert the decimal number 110 to binary (base 2), you divide the number by 2 successively and keep track of the remainders. 110 ÷ 2 = 55 remainder 0 55 ÷ 2 = 27 remainder 1 27 ÷ 2 = 13 remainder 1 13 ÷ 2 = 6 remainder 1 6 ÷ 2 = 3 remainder 0 3 ÷ 2 = 1 remainder 1 1 ÷ 2 = 0 remainder 1 Reading the remainders from bottom to top, the binary representation of 110 is 1101110.
you basically just write the point what ever at the top and then u put 100 at the bottom.
It isn't particularly difficult. Just use repeated divisions by 2; the remainders of each division give you the binary digit (in inverse order). Example: Convert 6 to binary. Dividing successively by 2 gives you: 6 / 2 = 3 r 0 3 / 2 = 1 r 1 1 / 2 = 0 r 1 Please note that you must continue until the result of the final division is equal to zero! The answer is 110 (the remainders, read from bottom to top). The above assumes a whole number; if you have decimals, additional calculations are required.
rock bottom remainders
1Set up the problem. For this example, let's convert the decimal number 15610 to binary. Write the decimal number as the dividend inside an upside-down "long division" symbol. Write the base of the destination system (in our case, "2" for binary) as the divisor outside the curve of the division symbol.This method is much easier to understand when visualized on paper, and is much easier for beginners, as it relies only on division by two.To avoid confusion before and after conversion, write the number of the base system that you are working with as a subscript of each number. In this case, the decimal number will have a subscript of 10 and the binary equivalent will have a subscript of 2.2 Divide. Write the integer answer (quotient) under the long division symbol, and write the remainder (0 or 1) to the right of the dividend.[2]Since we are dividing by 2, when the dividend is even the binary remainder will be 0, and when the dividend is odd the binary remainder will be 1.3 Continue to divide until you reach 0. Continue downwards, dividing each new quotient by two and writing the remainders to the right of each dividend. Stop when the quotient is 0.4Write out the new, binary number. Starting with the bottom remainder, read the sequence of remainders upwards to the top. For this example, you should have 10011100. This is the binary equivalent of the decimal number 156. Or, written with base subscripts: 15610 = 100111002This method can be modified to convert from decimal to any base. The divisor is 2 because the desired destination is base 2 (binary). If the desired destination is a different base, replace the 2 in the method with the desired base. For example, if the desired destination is base 9, replace the 2 with 9. The final result will then be in the desired base.
To convert the decimal number 54 into binary (base 2), we need to divide 54 by 2 repeatedly and keep track of the remainders. 54 divided by 2 equals 27 with a remainder of 0. 27 divided by 2 equals 13 with a remainder of 1. 13 divided by 2 equals 6 with a remainder of 1. 6 divided by 2 equals 3 with a remainder of 0. 3 divided by 2 equals 1 with a remainder of 1. 1 divided by 2 equals 0 with a remainder of 1. Reading the remainders from bottom to top, the binary representation of 54 is 110110.
The dividend is the numerator and the divisor is the denominator. Basically, you divide the top number (numerator) by the bottom number (denominator).
To convert the decimal number 23 to base 5, we divide the number by 5 and keep track of the remainders. Dividing 23 by 5 gives a quotient of 4 and a remainder of 3. Next, dividing the quotient 4 by 5 gives a quotient of 0 and a remainder of 4. Reading the remainders from bottom to top, 23 in base 5 is represented as 43.