Start with 1/98
Then, since adding and then subtracting 1/100 makes no difference.
= 1/100 + 1/98 - 1/100
= 1/100 + 2/9800
= 1/100 + 2/100*(1/98)
1/98 can thus be expressed in an iterative form where each iteration adds two digits of the pattern (2/100)n.
The iterative formula generates the pattern which persists as long as 2n is less than 100. After that the numbers overlap so that the 1 of the 128 get carried over to the 4 of the 64 so that the number is 0.0102040816326528
Then the 2 (of the next power of 2), 256 get carried over to the 8 to give
0.010204081632653056 so that the pattern is n longer recognisable.
You move the decimal 2 places over.
you just add a decimal to were you want it to go....
If you repeat the pattern, adding one more zero every time, then no. To qualify as a "repeating decimal", the same digits have to repeat over and over.
Divide 4.000.. by 9, as a long division, but make sure the decimal point for the answer is directly above the decimal point for 4.000... This should give you 0.444...
49 over 100, in decimal form is 0.49; the rest of the question does not make sense.
You move the decimal 2 places over.
It is the decimal approximation to the value of the irrational number.
17/19 as a decimal = 0.8947
0.3125
1.25
A decimal is a rational number if:* It terminates - i.e., it has a finite number of decimal digits. * It doesn't terminate, but it repeats the same pattern over and over - possibly after a finite number of digits that are not included in the pattern. For example, 0.145145145145..., or 3.125252525...
you just add a decimal to were you want it to go....
1.06
If you repeat the pattern, adding one more zero every time, then no. To qualify as a "repeating decimal", the same digits have to repeat over and over.
Make it a decimal 2.875
0.6666 repeating
percent of increase-new-original over originalthen make the decimal a percent of increasepercent of decrease-original-new over originalthen make the decimal a percent of decrease