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Surface area of a sphere (the golfball) = 4*pi*radius2 square cm
The density of golfball is less then density of water
4pr2 p being pi r being the radius. Then I guess you'd need to take into account all the area added by the dimples. Not sure about getting an exact, but would be interested to know. Do the dimples add or subtract from the surface area? I would guess it adds.
An odd number of dimples would render the ball asymmetrical.
there is many things... :bubble,moon,earth, golfball, smile face, doughnuts......