It works because a trapezoid is made up of two triangles , both with the same altitude, that altitude being the height of the trapezoid. If the bases ( i.e parallel sides are a and b and the height is h. one triangle has area 1/2ah and the other 1/2 bh so the total area is
1/2ah+ 1/2bh = 1/2h(a+b).
You need to use BODMAS whenever you evaluate ANY formula.
Add the four sides.
1/2h(b1+b2) =D
Area = base*height
The answer depends on what x is. And also, it is a trapezoid, not trapizoid!
You need to use BODMAS whenever you evaluate ANY formula.
Add the four sides.
1/2h(b1+b2) =D
To find the area of a object you do width x highth for a rectangle. You multiply on side of the object 4 times to get the area of a square. To find the area of a trapizoid, the formula is, 1/2 times highth (base 1 plus base 2).
It says so in the formula
Area = base*height
The formula for the area of a rectangle is length x breadth. In order to prove this works, work out an area of a rectangle using that formula.
There are zero right angles in a trapizoid............
A TRAPIZOID has 2 lines of symmetry
a formula is alway correct
Most probably because there is no such word as trapizoid. A trapezoid is a quadrilateral.
The answer depends on what x is. And also, it is a trapezoid, not trapizoid!