The simplest answer is - because it is only defined for n = 0 (0! = 1) and n > 0 (n! = (n-1)! x n).
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3!(factorial) or six
To calculate the number of zeros in a factorial number, we need to determine the number of factors of 5 in the factorial. In this case, we are looking at 10 to the power of 10 factorial. The number of factors of 5 in 10! is 2 (from 5 and 10). Therefore, the number of zeros in 10 to the power of 10 factorial would be 2.
It can be calculated as factorial 44! = 4x3x2x1= 60
P(n,r)=(n!)/(r!(n-r)!)This would give you the number of possible permutations.n factorial over r factorial times n minus r factorial
factorial of -1