for any non zero no. x, x^0=1
the proof is as follows, consider the two no.s x^m and x^n,where m and n are two non zero no.s. now let us assume without any oss of generality,that m>n,hence (x^m)/x^n=(x*x*x....m times)/(x*x*x...n times)
now on the r.h.s, n no. of x in the denominator will cancel out n no. of x in the numerator(as x is non zero);leaving (m-n) no. of x in the numerator,
i.e. (x^m)/(x^n)=x^(m-n)
now letting m=n,we have
x^m/x^m=x^(m-m)
or, 1=x^0
hence the proof
if x is also 0,i.e. 0 to the power 0 is undefined!
Chat with our AI personalities
If they are both equal the answer will be zero.E.g.1/4 - 1/4 =(1 - 1 = 0)0/4 = 0
It is like a pattern. 4^4=64 4^2=16 4^1=4 4^0=1 as the exponent gets smaller the result is divided by 4.
Zero.
0 (1-1)/4 = 0/4 = 0
Anything to the power 0 is 1. 4 × 10^0 = 4 × 1 = 4.