Any negative number to the power of 0 is always -1
Anything to the power of 0 has an answer of 1. So 7⁰ = 1, as well as any other number you can think of.
7^0 = 1.
5x2 + 12x + 7 = 0 This equation can be factored : (5x + 7) (x + 1) = 0 The equation equals zero when either 5x + 7 = 0 or x + 1 = 0 When 5x + 7 = 0 then 5x = -7 : x = -7/5 or -1.4 When x + 1 = 0 then x = -1 The solutions or roots of this equation are x = -7/5 and x = -1
16
Why is 7^0 = 1 Algebraic proof. Let 'n' be any value Let 'n be raised to the power of 'a' Hence n^a Now if we divide n^a by n^a we have n^a/n^a and this cancels down to '1' Or we can write n^(a)/n^(a) = n^(a-a) = n^(0) , hence it equals '1' Remember when the lower /denominating index is a negative power ,when raised above the division line.
Any negative number to the power of 0 is always -1
71 is greater.
One.
Anything to the power of 0 has an answer of 1. So 7⁰ = 1, as well as any other number you can think of.
7^0 = 1.
Any value to the power of 'zero' is equal; to '1' So 7^0 = 1 Similarly 7,000,000^0 = 1 Similarly 0.000007^0 = 1
5x2 + 12x + 7 = 0 This equation can be factored : (5x + 7) (x + 1) = 0 The equation equals zero when either 5x + 7 = 0 or x + 1 = 0 When 5x + 7 = 0 then 5x = -7 : x = -7/5 or -1.4 When x + 1 = 0 then x = -1 The solutions or roots of this equation are x = -7/5 and x = -1
7-1 equals 0.14285714285
The answer is [ x = 1/7 ].
There is a formula for "the difference of squares." (x + 7)(x - 7) = 0 x = 7, -7
8 - 1 = 7