Because density expressed in two significant figures depends on your accuracy of your measurements of mass and volume to calculate as well as any variables that you are expected to use.
The number 355,000 expressed in two significant figures is 360,000. In this case, the first two significant figures are '3' and '5', and since the next digit (5) is 5 or greater, we round up the last significant figure, resulting in '6'. Therefore, 355,000 rounded to two significant figures is 360,000.
When multiplying numbers, the result should reflect the least number of significant figures in any of the factors. In this case, 0.0090 has two significant figures, and 87.10 has four significant figures. Therefore, when multiplying these two numbers, the result must be expressed with two significant figures, leading to a final answer that reflects this precision.
The number 151.208, when expressed to two significant figures, is 150. This is because the first two significant figures are '1' and '5', and rounding the next digit (which is '1') leads to a decrease in the last significant figure. Therefore, the rounded value is 150.
460. (the period/decimal point is necessary; otherwise 460 would be considered two significant figures)
If you know the density of mercury, you can determine the mass of a specific volume of mercury. Mercury has a density of 13.534g/cm3. 1cm3 = 1mL, so we can restate its density as 13.534g/mL. Density = mass/volume. If we know any two variables, we can manipulate the density equation to find the third variable. In this case, we know volume and density, so to find the mass, do the following calculation: Mass = density x volume Mass Hg = 13.534g/mL x 136mL = 1.84g Hg* *The answer is limited to 3 significant figures, because 136mL has only 3 significant figures, even though the density has 5 significant figures. When multiplying or dividing, the answer is limited to the same number of significant figures as the measurement with the fewest significant figures used in the calculation.
It is not always expressed in 2 sig figs. The number of sig figs depends on the accuracy of your measurements of mass and volume to calculate the density as well as any variables that you are expected to use the density with. There is no point in having a density expressed to 15 significant figures if then you are going to multiply it by volume expressed to 1 sig fig to determine the mass.
The atomic mass of Cu-63 should be expressed to two significant figures, which are 63.
It is: 62 kg
The number 355,000 expressed in two significant figures is 360,000. In this case, the first two significant figures are '3' and '5', and since the next digit (5) is 5 or greater, we round up the last significant figure, resulting in '6'. Therefore, 355,000 rounded to two significant figures is 360,000.
When multiplying numbers, the result should reflect the least number of significant figures in any of the factors. In this case, 0.0090 has two significant figures, and 87.10 has four significant figures. Therefore, when multiplying these two numbers, the result must be expressed with two significant figures, leading to a final answer that reflects this precision.
There are four significant figures in 149.0. The trailing zero after the decimal point indicates that it is significant.
The number 151.208, when expressed to two significant figures, is 150. This is because the first two significant figures are '1' and '5', and rounding the next digit (which is '1') leads to a decrease in the last significant figure. Therefore, the rounded value is 150.
460. (the period/decimal point is necessary; otherwise 460 would be considered two significant figures)
There are 4 significant figures in 0.0032. Seems to be only 2 significant figures in this number.
There are two significant figures which are the two 2s.
all the zeros are significant. there are four significant figures.
If you know the density of mercury, you can determine the mass of a specific volume of mercury. Mercury has a density of 13.534g/cm3. 1cm3 = 1mL, so we can restate its density as 13.534g/mL. Density = mass/volume. If we know any two variables, we can manipulate the density equation to find the third variable. In this case, we know volume and density, so to find the mass, do the following calculation: Mass = density x volume Mass Hg = 13.534g/mL x 136mL = 1.84g Hg* *The answer is limited to 3 significant figures, because 136mL has only 3 significant figures, even though the density has 5 significant figures. When multiplying or dividing, the answer is limited to the same number of significant figures as the measurement with the fewest significant figures used in the calculation.