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All sides (edges) of a cube are of equal lengths. And because of symmetry, any face of the cube can end up as the base. So it is sufficient if we find the area of any one face which would be the (length of any one edge) multiplied by itself. Hence it is (length of any one edge) x (length of any one edge)
If the length of each edge of the cube is 's',then the area of each face is s2.
2 ft
One side or edge times another. (length x width = area)
You would have to specify the shape for which we are finding these quantities. But let us say that it is a cube, which is the easiest. The length of an edge of the cube, multiplied by itself gives the area of a face, and multiplied by itself again gives the volume. So the cube root of the volume is the edge length, and then the square of the edge length is the surface area of one face of the cube, which multiplied by 6 gives the area of the entire cube.
A+ BCD Roxy(;
The planar density of a 100 plane in a face-centered cubic (FCC) structure can be calculated by counting the atoms along the edge of the plane. For a 100 plane in FCC, there are 2 atoms along the edge in the [100] direction. The formula to calculate planar density is (number of atoms along the edge) / (edge length * sqrt(2)).
ACD
Length of one side=2 cm24/6 = 4 . If a face (square) has an area of 4 then the length of each edge is 2.
square
The edge length of a sodium chloride (NaCl) unit cell is approximately 5.64 Å.
All sides (edges) of a cube are of equal lengths. And because of symmetry, any face of the cube can end up as the base. So it is sufficient if we find the area of any one face which would be the (length of any one edge) multiplied by itself. Hence it is (length of any one edge) x (length of any one edge)
If the length of each edge of the cube is 's',then the area of each face is s2.
2 ft
The face diagonal of an fcc unit cell can be calculated using the relationship: face diagonal = √2 * edge length. Given the edge length of 350.7 pm, the face diagonal would be 495.2 pm. Since the atom sits on the body diagonal, the radius of a nickel atom can be calculated as half the body diagonal, which is (1/√3) * face diagonal. Calculating this gives a radius of approximately 202.1 pm.
It depends on the angle of the plane of the cross section. If it is parallel to the cube's face (or equivalently, two adjacent edges) the cross section will be a square congruent to the face. If the plane is parallel to just one edge (and so angled to a face), the cross section will be a rectangle which will have a constant width. Its length will increase, remain at a maximum level and then decrease. If neither, it will be a hexagon-triangle-hexagon-triangle-hexagon (triangles when passing through a vertex).
One side or edge times another. (length x width = area)