Take any fraction x/y and multiple that by it's reciprical, y/x. The result is x*y/x*y, or one. so any positive fraction multiplied by it's reciprical is one. hope that helped :)
Suppose x and y are two POSITIVE numbers so that -x and -y are negative. Then a negative minus a negative = (-x) - (-y) = -x +y If x > y the answer is negative If x = y the answer is zero If x < y the answer is positive
2
No, it can also be zero or negative, depending on their magnitudes.
Let X = *positive number 1* Let Y = *positive number 2* X times Y
Cartesian coordinates.
X comes first :)
X:83 y:20
X-56 & y-52.
X 73 Y 83 - Ice Planet
the x axis come first then the y axis
Short answer: Yes. Long answer: it depends on the order. If x is negative and y is positive, then x-y<0; y-x>0 (this second one is only correct if |y|<>|x|). And if |y|=|x| then y-x=0 (this is the one you're looking for, where x and y are equal, but y is positive and x is negative). Finally, if you know if |y|=|x| or |y|<>|x| then y-x>=0
Quadrant I: x positive, y positive. Quadrant II: x negative, y positive. Quadrant III: x negative, y negative. Quadrant II: x positive, y negative.
Take any fraction x/y and multiple that by it's reciprical, y/x. The result is x*y/x*y, or one. so any positive fraction multiplied by it's reciprical is one. hope that helped :)
Let x and y be two positive numbers. The cases are: x > y, then x - y > 0 x = y, then x - y = 0 x < y, then x - y < 0
The difference between a positive integer and a negative integer is ALWAYS positive.Suppose X and Y are positive so that -Y is negative,The the difference two numbers, A and B is A - B so the difference between X and (-Y) is X - (-Y) which equals X + Y. The sum of two positive numbers is always positive.
There are four quadrants. They are represented by Roman numerals : I(one), II(two), III(three), IV(four). The first quadrant contains all positive points , (+x, +y) The second quadrant contains negative x's and positive y's , (-x, +y) The third quadrant is all negative , (-x, -y) The fourth quadrant has negative y's and positive x's , (+x, -y)