0
I'm assuming you are referring to the equation for a line: y = mx + b, and that you are wondering why the m (which represents the slope of the line) not represented with the letter 'g'. Mathematicians are basically just making up names for values that they don't know the meaning of yet (these are called variables). They could just as easily picked the letter 'g', but instead they picked 'm'. This has been around so long that it has become the standard notation for it, and it is unlikely to change any time soon.
I don't know if that answers your question or not, but hopefully it helps.
What else can I help you with?
When equation is given in the form ymx plus c then slope is?
If you mean: y = mx+c then m is the slope and c is the y intercept
Is y equals mx plus c a sraight line?
Yes, with slope m and y-intercept = (0,c).
How it can be expressed in the form of ax plus by plus c equals 0?
The answer depends on "it" being the equation of a straight line and your starting point for "it". The equation of a straight line can be written as y = mx + c where m is the slope or gradient of the line and c is the intercept. Simple rearrangement of the terms gives: mx - y c = 0 and that is in the required form with m = a, -1 = b and c = c.
What are the formulas of the equation of the line?
Standard: Ax+By=C (A must be positive; A, B, and C must be integers) Point-slope: y-h=m(x-k) ((k,h) is a point on the line, m is the slope) slope-intercept: y=mx+b (m is the slope, b is the y-intercept)
Function of y equals mx plus c?
The equation y = mx + c, is the equation of a line in slope-intercept form. The m term is the slope or first order deriviative (dy/dx) of the line, and the c term is the y-axis intercept.
Y equals mx plus c what is m and c?
well, m is the slope and c is the y-intercept
Can you write an equation for a non proportional linear relationship?
Yes. y = mx + c where m and c are non-zero constants.Yes. y = mx + c where m and c are non-zero constants.Yes. y = mx + c where m and c are non-zero constants.Yes. y = mx + c where m and c are non-zero constants.
When equation is given in the form ymx plus c then slope is?
If you mean: y = mx+c then m is the slope and c is the y intercept
Is y equals mx plus c a sraight line?
Yes, with slope m and y-intercept = (0,c).
How it can be expressed in the form of ax plus by plus c equals 0?
The answer depends on "it" being the equation of a straight line and your starting point for "it". The equation of a straight line can be written as y = mx + c where m is the slope or gradient of the line and c is the intercept. Simple rearrangement of the terms gives: mx - y c = 0 and that is in the required form with m = a, -1 = b and c = c.
Y equals -4x plus 9 find the slope?
slope = -4 for y=mx+c, slope=m, y intercept=c
How do solve for m Y equals mx plus 6?
Y = mX + 6 Y - 6 = mX (Y - 6)/X = m ==============If you had values you could get the integer that is m
What are the formulas of the equation of the line?
Standard: Ax+By=C (A must be positive; A, B, and C must be integers) Point-slope: y-h=m(x-k) ((k,h) is a point on the line, m is the slope) slope-intercept: y=mx+b (m is the slope, b is the y-intercept)
How do you change y equals mx plus b to Ax plus By plus C equals 0?
Just subtract y from both sides. 'm' becomes 'A', 'b' becomes 'C' and 'B' will be equal to one.
How do you Solve the formula y equals mx plus b for M?
the answer is: (y-b)/x = m y = mx + b y - b = mx (y-b)/x = m
Function of y equals mx plus c?
The equation y = mx + c, is the equation of a line in slope-intercept form. The m term is the slope or first order deriviative (dy/dx) of the line, and the c term is the y-axis intercept.
How do you change point-slope to slope-intercept?
Given the point P = (a, b) and slope m, the point-slope equation is(y - b) = m*(x - a)y - b = mx - may = mx - ma + bwhich can be re-written asy = mx + (b - ma) which is of the slope-intercept form y = mx + c in which c = b - ma.Given the point P = (a, b) and slope m, the point-slope equation is(y - b) = m*(x - a)y - b = mx - may = mx - ma + bwhich can be re-written asy = mx + (b - ma) which is of the slope-intercept form y = mx + c in which c = b - ma.Given the point P = (a, b) and slope m, the point-slope equation is(y - b) = m*(x - a)y - b = mx - may = mx - ma + bwhich can be re-written asy = mx + (b - ma) which is of the slope-intercept form y = mx + c in which c = b - ma.Given the point P = (a, b) and slope m, the point-slope equation is(y - b) = m*(x - a)y - b = mx - may = mx - ma + bwhich can be re-written asy = mx + (b - ma) which is of the slope-intercept form y = mx + c in which c = b - ma.
