Let x, y and z be even numbers. This means that (x + 1), (y + 1) and (z + 1) are all odd. Adding these three odd numbers gives (x + y + z + 3). Because the sum of any number of evens must be even as well - which can be easily proven with idea that where a = 2m and b = 2n, a + b = 2m + 2n = 2(m + n), and is even - adding 3 changes it to an odd number. This holds for any set of three odd numbers.
i agree with this... but what about in the form of 2n+1?
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The sum of three odd numbers will be odd, whether they are prime or not. The sum of three prime numbers can be even as long as one of them is 2.
There are no such numbers. The sum of any three odd numbers must be odd. 112 is not.
Because the sum of two odd numbers is always even and the sum of that even number plus another odd number is always odd.
That isn't possible. The sum of three odd numbers will always be odd. You can make the sum of 3 prime numbers equal to 32 if one of them is 2 (which is not odd).
The first three odd numbers are 1, 3, and 5. Their sum is 1 + 3 + 5 = 9.