Water has a weight. The more you stack up the more it weighs. There fore if you stack up 10 meters or 20 meters it makes a big difference.
The water pressure depends only on the depth, not on the size or shape of the vessel. The pressure increases at about 1 atmosphere (or bar) every 10 meters.
Twelve fathoms
500 acres is 21,780,000 square feet. Assuming dthe depth is greater than the width, the depth can be any number greater than sqrt(21780000) = 4666.91 ft. Suppose the depth is D feet then a rectangular area with width = 21780000/D will have an area of 21780000 sq ft or 500 acres.
Pressure in seawater at 100 feet is 44 psi. Or, .44 pounds per square inch per 1 foot. For Fresh water, it is .43 psi per foot.
Two atmospheres is 67.8 feet of water.
At 300 feet of water depth the pressure is about 130 psi
No. The pressure depends on the depth, and on the density of the liquid, which is presumably more or less the same in this case.
The 260 feet of water: at that depth, there is the weight of the water and the atmosphere on top of it.
Water pressure at a depth of about 44 feet is about 20psi
At 5,400 feet of water depth the pressure is about 2,341.1 psi
Approximately 60 atmospheres at that depth.
About 240 psi at 500 feet of depth.
About 21.4 psi
no clue bishes laffz
Pressure and depth are related in that pressure is proportional to depth. The equation to find pressure at a certain depth is p=dgh, where p is the pressure, d is the density, g is the acceleration of gravity and h is the depth.
406 meters / 1,332.02 feet of water depth has a pressure of about 39.3 atmospheres or 577.6 psi.
I'm sorry, but your question is so poorly crafted, it's very hard to interpret. Are you asking what device could be used to measure water pressure and depth? Or are you looking for a way to convert feet of air to feet or inches of water? One foot of water (at 4 degrees Celsius) is equivalent to 816.2 feet of air (at 15 degrees C).