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Each letter in polygon should only be used once to avoid confusion. Triangle CCC would not make sense. Angle LWL could be opposite from angle LWL in rectangle LWLW.

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Q: Why should each letter in a polygon only be used once?
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WhatEquilateral triangles and squares are what type of polygon?

why do each letter in the polygons name can only be used once??? why do each letter in the polygons name can only be used once???


Why do can each letter in a polygon's name be used only once?

That's not necessarily true. An octagon is an eight-sided polygon with two 'o's


Why do you think each letter in a polygons name can be used only once?

Because every point must have its own name to identify it from


Do you have any pictures of polygons?

Why do you think each letter in a polygon's name can be used only once? ____________________________________________________ ______________/\ _____________/-- \ ____________/ -----\ ___________/______\ Its called triangle :)


Why can each letter in a polygon only be used once?

To avoid confusion as to which vertex or side you are talking about.


Why does each letter in a polygon name can only be used once?

because every point must have its own name to identify it from others.


Why can you only use the same letter once when naming a polygon?

You use the same letter only once when naming a polygon (or parts of a polygon) to avoid ambiguity. If you have two line segments both labelled A, then you won't know which one you mean when you talk about segment A, right?


How many times does each line segment in a polygon intersect?

I want to say 2, once at each corner


Why can you only use a letter one time in a polygon?

I think it is used once because it is no fair that one letter get to be used twice and the another letters are used once


Why can a letter be used only once in a polygon?

Because if you gave more than one side the same letter - it would get confusing !


Why do a polygon can be used only once?

A polygon can be used infinitely many times!


How many diagonals will an -sided polygon have?

An n-sided polygon wil have n*(n-3)/2 diagonals.Consider joining each vertex to every other vertex. That gives potentially n-1 vertices. However, two of these will be sides of the polygon and so not diagonals. So each vertex gives rise to (n-3) diagonals. There are n vertices in the polygon and so that gives n*(n-3) diagonals. But, this method counts each diagonal twice: once from each end and so the correct answer is n*(n-3)/2.