The cosecant is the reciprocal of the sine function. Now, the reciprocal of a positive number is positive, and the reciprocal of a negative number is negative.
its the inverse of cosecant theta.
Cotangent = 1/Tangent : Cosecant = 1/Sine Then, cot + 1 = (1/tan) + 1 = (cos/sin) + (sin/sin) = (cos + sin)/ sin. Now, cos² + sin² = 1 so for the statement to be valid the final expression would have to be : (cos² + sin² ) / sin = 1/sin. As this is not the case then, cot + 1 ≠ cosec. In fact, the relationship link is cot² + 1 = cosec²
Cosecant(Csc) = 1 / Sin . Hence its recip[rocal is 'Sin'(Sine). Similarly Secant(Sec) = 1/ Cos . Hence its reciprocal is 'Cos'(Cosine) Cotangent(Cot) = 1 /Tan . Hence its reciprocal is 'Tan'(Tangent).
We're not sure how you wrote the question.If you wrote it as a subtraction: [ cosecant minus 1 ] = sine, then no, that's false.If you wrote it as an exponent: [ cosecant to the -1 power ] = sine, then yes, that's true.1 / csc(x) = sin(x)
Express the cosecant in terms of sines and cosines; in this case, csc x = 1 / sin x. This can also be written as (sin x)-1. Remember that the derivative of sin x is cos x, and use either the formula for the derivative of a quotient (using the first expression), or the formula for the derivative of a power (using the second expression).
Yes: cosecant = 1/sine If sine negative, 1/sine is negative → cosecant is negative.
cosecant(x) = 1/sin(x)
Sine Its reciprocal is Cosecant Algebraically Sin ; Reciprocal is '1/ Sin' known as 'Cosecant(Csc)'. Similarly Cos(Cosine) ; 1/ Cos (Secant(Sec)) Tan(Tangent) ; 1/ Tan ( Cotangent(Cot)).
Cosecant is the reciprocal of sine. To find the cosecant of an angle using a calculator, find the sine of that angle (using the Sin button) and then divide 1 by the result.
its the inverse of cosecant theta.
Cotangent = 1/Tangent : Cosecant = 1/Sine Then, cot + 1 = (1/tan) + 1 = (cos/sin) + (sin/sin) = (cos + sin)/ sin. Now, cos² + sin² = 1 so for the statement to be valid the final expression would have to be : (cos² + sin² ) / sin = 1/sin. As this is not the case then, cot + 1 ≠ cosec. In fact, the relationship link is cot² + 1 = cosec²
The answer depends on what you mean by "vertical of the function cosecant". cosec(90) = 1/sin(90) = 1/1 = 1, which is on the graph.
Cosecant(Csc) = 1 / Sin . Hence its recip[rocal is 'Sin'(Sine). Similarly Secant(Sec) = 1/ Cos . Hence its reciprocal is 'Cos'(Cosine) Cotangent(Cot) = 1 /Tan . Hence its reciprocal is 'Tan'(Tangent).
We're not sure how you wrote the question.If you wrote it as a subtraction: [ cosecant minus 1 ] = sine, then no, that's false.If you wrote it as an exponent: [ cosecant to the -1 power ] = sine, then yes, that's true.1 / csc(x) = sin(x)
Sin(30) + cosec(30) = sin(30) + 1/sin(30) = 0.5 + 1/0.5 = 0.5 + 2 = 2.5
Express the cosecant in terms of sines and cosines; in this case, csc x = 1 / sin x. This can also be written as (sin x)-1. Remember that the derivative of sin x is cos x, and use either the formula for the derivative of a quotient (using the first expression), or the formula for the derivative of a power (using the second expression).
the sin and csc functions are reciprocals, & reciprocals always have the same sign, since their product is 1, a positive number (straight out the back of a precalc book)