To determine if a solid cube with 6-cm sides and a mass of 270 g would float, we need to calculate its density and compare it to the density of water. The volume of the cube is (6 , \text{cm} \times 6 , \text{cm} \times 6 , \text{cm} = 216 , \text{cm}^3). The density of the cube is ( \frac{270 , \text{g}}{216 , \text{cm}^3} \approx 1.25 , \text{g/cm}^3), which is greater than the density of water (1 g/cm³). Therefore, the cube would not float.
H
a cube
A CUBE
A cube has six faces (sides).
It wouldn't be a cube if the sides aren't equal in length. It would be called a rectangular prism.
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Volume of cube = 6^3 = 216 cm^3 Density of cube = 270 g / 216 cm^3 = 1.25 g cm^-3 This cube would not float in water as its density is greater than the density of water at 1 g cm^3
a cube
A CUBE
A cube has six faces (sides).
It wouldn't be a cube if the sides aren't equal in length. It would be called a rectangular prism.
it's a solid
the solid figure with six congruent sides isva cube
A cube.
Cube
CUBE
A cube would fit the given description