implicit double precision(a-h,o-z)
write(*,*) "please provide the a,b,c coeff"
read(*,*) A,B,C
D=B*B-4*A*C
if(D.GT.0) then
root1=(-B/(2*A))+(SQRT(D))/(2*A)
root2=(-B/(2*A))-(SQRT(D))/(2*A)
write(*,*) root1,root2
elseif(D.EQ.0) then
root1=(-B/(2*A))
root2=root1
write(*,*) root1,root2
else
root1=(-B/(2*A))+(SQRT(-D))/(2*A)
root2=(-B/(2*A))-(SQRT(-D))/(2*A)
a=(root1+root2)/2
b=(root1-root2)/2
write(*,*) 'realpartroot=',a, 'complexpartroot=',b
endif
stop
END
computer scince
ax2 + bx + c
Write the quadratic equation in the form ax2 + bx + c = 0 The roots are equal if and only if b2 - 4ac = 0. The expression, b2-4ac is called the [quadratic] discriminant.
First, write the equation in standard form, i.e., put zero on the right. Then, depending on the case, you may have the following options:Factor the polynomialComplete the squareUse the quadratic formula
You do not need to write anything to calculate things mentally.
dejene
Write an algorithm to find the root of quadratic equation
Solve simple intress usin fortran
readuse the answer
2000X=Y2KoverZzz?
Write the quadratic equation in the form ax2 + bx + c = 0 then the roots (solutions) of the equation are: [-b ± √(b2 - 4*a*c)]/(2*a)
computer scince
ax2 + bx + c
Write the quadratic equation in the form ax2 + bx + c = 0 The roots are equal if and only if b2 - 4ac = 0. The expression, b2-4ac is called the [quadratic] discriminant.
Yes. The FORTRAN write command output's data to a file.
First, write the equation in standard form, i.e., put zero on the right. Then, depending on the case, you may have the following options:Factor the polynomialComplete the squareUse the quadratic formula
The easiest way to write a generic algorithm is to simply use the quadratic formula. If it is a computer program, ask the user for the coefficients a, b, and c of the generic equation ax2 + bx + c = 0, then just replace them in the quadratic formula.