divisible by 2 means even number. so it can not be even number.
divisible by 3 means add all the number and divide 3..number 99 is divisible by 3 we start 99+3=102 but it is even number..105,108,111,114,117,120. (108,114,120 are even number so
they can not be answer) answers are 105, 111,117.
The number is 90.
To find the numbers between 50 and 100 that are divisible by 3, we can use the formula for finding the number of integers divisible by a certain number within a range. The formula is (largest number - smallest number) / divisor + 1. In this case, the largest number is 99, the smallest number is 51, and the divisor is 3. Plugging these values into the formula, we get (99 - 51) / 3 + 1 = 16. Therefore, there are 16 numbers between 50 and 100 that are divisible by 3.
90
There are 2,966 numbers between 100 and 9,000 that are divisible by three.
It is 120, 150, and 180.
The number is 90.
To find the total number of integers between 100 and 300 that are divisible by 3, we first determine the smallest and largest integers in this range that are divisible by 3. The smallest integer divisible by 3 is 102, and the largest is 297. To find the total number of integers between 102 and 297 that are divisible by 3, we calculate (297-102)/3 + 1, which equals 66. Therefore, there are 66 integers between 100 and 300 that are divisible by 3.
To find the numbers between 50 and 100 that are divisible by 3, we can use the formula for finding the number of integers divisible by a certain number within a range. The formula is (largest number - smallest number) / divisor + 1. In this case, the largest number is 99, the smallest number is 51, and the divisor is 3. Plugging these values into the formula, we get (99 - 51) / 3 + 1 = 16. Therefore, there are 16 numbers between 50 and 100 that are divisible by 3.
251
90
105
It is 90.
There are 67 numbers between 100 and 500 divisible by 6. The first number greater than 100 divisible by 6: 100 ÷ 6 = 16 r 4 → first number divisible by 6 is 6 × 17 = 102 Last number less than 500 divisible by 6: 500 ÷ 6 = 83 r 2 → last number divisible by 6 is 6 × 83 = 498 → all multiples of 6 between 17 × 6 and 83 × 6 inclusive are the numbers between 100 and 500 that are divisible by 6. → there are 83 - 17 + 1 = 67 such numbers.
To find a number between 80 and 100 that is divisible by both 5 and 6, we need to find the least common multiple (LCM) of 5 and 6, which is 30. We then look for a multiple of 30 between 80 and 100, which is 90. Therefore, the number 90 between 80 and 100 is divisible by both 5 and 6.
150
72 and 100 is divisible by 2.
No. For a number to be divisible by 100 it needs to be a whole number and end in 00.