0.8 0.04 0.53
0.27, 0.99, 1.8, 2.01
0.05, 0.5, 5.5, .55
Working left to right, like reading a sentence, you write the fractions from smallest to largest, thus putting them in order. If the directions say "largest to smallest", then you write them in that order. For example, 1/4 is less than 1/2, 1/2 is less than 3/4 so the order would be (from smallest to largest) 1/4, 1/2, 3/4 Hope this helps.
The smallest 5 digit number you can write is 10000.
smallest: zero largest: five thousand
just go the reverse of how they are listed now they are currently largest to smallest
Asia and Australia are continents.
final double[] ns = new double[10]; final Random rnd = new Random(System.currentTimeMillis()); // Fill... for (int i = 0; i < ns.length; ++i) { ns[i] = rnd.nextDouble(); } // Get largest/smallest... double largest = Double.MIN_VALUE; double smallest = Double.MAX_VALUE; for (double n : ns) { if (n > largest) { largest = n; } if (n < smallest) { smallest = n; } } // largest and smallest are now the proper values.
0.8 0.04 0.53
A sentence using the names of the largest and smallest continents would be "Sarah is going on a tour of the world and she going to visit Asia and Australia. North America is the 3rd largest continent.
Name two variables x and y. Divide the largest by smallest. If remainder is zero then the smallest is the HCF.
I flew from a plane from Asia to Australia in one night
0.05, 0.5, 5.5, .55
0.27, 0.99, 1.8, 2.01
Working left to right, like reading a sentence, you write the fractions from smallest to largest, thus putting them in order. If the directions say "largest to smallest", then you write them in that order. For example, 1/4 is less than 1/2, 1/2 is less than 3/4 so the order would be (from smallest to largest) 1/4, 1/2, 3/4 Hope this helps.
Use the following algorithm (written in pseudocode). Let largest be the lowest possible real number. Let smallest be the greatest possible real number. Repeat while there is input... { Read real number r from input. If r is greater than largest then let largest be r. If r is less than smallest then let smallest be r. } End repeat. Let range be largest minus smallest. Output range.