That factors to (x - 14)(x - 2)
x2+12x+28Improved Answer:--x2+12x+28 = (-x+14)(x+2) when factored
(x - 14)(x - 2)
If: 16x-15-6x = 13 Then: 10x = 28 And: x = 2.8.
To make the polynomial ( x^2 - 28x + ? ) a perfect square trinomial, we need to find the value that completes the square. The formula for a perfect square trinomial is ( (x - a)^2 = x^2 - 2ax + a^2 ). Here, ( a ) is half of the coefficient of ( x ), which is ( -28 ). Thus, ( a = 14 ), and we need ( a^2 = 196 ). Therefore, the value in place of the question mark is ( 196 ).
28 + 28 = 56.56 + 28 = 84.
x2 - 16x + 28 = (x - 2)(x - 14). Even though you don't mention any factors below, it is easy to tell that the above-given two factors must be the ones you are looking for. If (14 - x) and (2 - x) are mentioned in your list, they would be good, also.
x2+12x+28Improved Answer:--x2+12x+28 = (-x+14)(x+2) when factored
(x - 14)(x - 2)
I would do this. Multiply through by -1 -1 ( -X^2 +12X +28 ) = X^2 -12X -28 (X+2)(X-14)
Oh, dude, you've thrown me back to high school math class with that one. So, X2 - 16x + 28 is a quadratic expression that can be factored as (X - 14)(X - 2). That's like the math version of solving a puzzle, but like, who even uses this stuff in real life, am I right?
If: 16x-15-6x = 13 Then: 10x = 28 And: x = 2.8.
28 + 28 = 56.56 + 28 = 84.
22+22+28+28=100.
-26
28 + 28 = 56
The answer is 56
2058+245+28+2 = 2333