x2+12x+5 = 3 x2+12x+5-3 = 0 x2+12x+2 = 0
168
x2 + 12x - 64 = 0 ∴ (x + 16)(x - 4) = 0 ∴ x ∈ {4, -16}
It is -13.
x2+12x+28Improved Answer:--x2+12x+28 = (-x+14)(x+2) when factored
x2+12x+5 = 3 x2+12x+5-3 = 0 x2+12x+2 = 0
168
x2 + 12x - 64 = 0 ∴ (x + 16)(x - 4) = 0 ∴ x ∈ {4, -16}
It is -13.
x2+12x+28Improved Answer:--x2+12x+28 = (-x+14)(x+2) when factored
x2+12x+36=0 2x+12x+36=0 14x+36=0 14x=-36 x=-36/14 x=-2 4/7
x=5/2*sqr(3)
x2 + 12x + 27 = (x + 9)(x + 3)
x2-12x+36 = (x-6)2
x2+12x-13=0 The factor of x2+12x-13 is: (x+13)(x-1) So: x+13 = 0 or x-1 = 0 The answer is: x=-13 or x=1
If you're looking to solve for x, you can do so as follows: x2 + 12x - 6 = 0 x2 + 12x + 36 = 42 (x + 6)2 = 42 x + 6 = ± √42 x = -6 ± √42
x2+12x+11=0 (x+11)(x+1)=0 x=-11 or x=-1