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I think this is how you do it:

x2+2x = 8

x2+2x+(1/2*(2))2 = 8 + (1/2*(2))2

x2+2x+1=8+1

(x+1)2 = 9

SQ.ROOT [(x+1)2 = 9]

x+1 = 3 and x+1 = -3

so,

x=2 and x=-4

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14y ago

What else can I help you with?