I think this is how you do it:
x2+2x = 8
x2+2x+(1/2*(2))2 = 8 + (1/2*(2))2
x2+2x+1=8+1
(x+1)2 = 9
SQ.ROOT [(x+1)2 = 9]
x+1 = 3 and x+1 = -3
so,
x=2 and x=-4
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This quadratic equation has no solutions because the discriminant is less than zero.
It cannot be solved because the discriminant of the quadratic equation is less than zero
it equals 13X.
-2x plus 3y equals 1
X=7