x2 + 49 = x2 - (-49) = x2 - (-1)(49) = x2 - (i2)(72) = x2 - (7i)2 = (x - 7i)(x + 7i) where i is the imaginary square root of -1.
x2 + 49 = 0 ∴ x2 = -49 ∴ x = 7i
x2+14x+49 = (x+7)(x+7) when factored
x2 + y - 49 = 0At the x-intercepts, y=0:x2 - 49 = 0(x+7)(x-7) = 0x = -7 and x = +7At the y-intercept, x=0:y - 49 = 0y = 49
(x-7) (x-7)
(x2 + 14x + 49) = (x + 7)2
x2 + 49 = x2 - (-49) = x2 - (-1)(49) = x2 - (i2)(72) = x2 - (7i)2 = (x - 7i)(x + 7i) where i is the imaginary square root of -1.
x2 - 14x + 49(x - 7) (x - 7)
x2 + 49 = 0 ∴ x2 = -49 ∴ x = 7i
x2+14x+49 = (x+7)(x+7) when factored
x2 - 14x + 49 = (x - 7)2
x2 + y - 49 = 0At the x-intercepts, y=0:x2 - 49 = 0(x+7)(x-7) = 0x = -7 and x = +7At the y-intercept, x=0:y - 49 = 0y = 49
(x-7) (x-7)
49 x2 + 14x = -7 x2 + 14x + 49 = 42 (x + 7)2 = 42 x = -7 ± √42
x2-49 = (x-7)(x+7)
(x + 7)(x2 - 7x + 49)
Yes because if x2-14x+49 then it is (x-7)(x-7) when factored