(4, -1)
The ordered pair is (3, 2).
The ordered pair is (2, 3).
x = 4 and y = -1 (4. -1)
i am guessing here that this is what you mean as it involves substitution: 2x-2y = 4 therefore -2y = 4 - 2x Sub the above line into the first equation gives: 13x - 2x +4 = 70 11x = 66 x=6 then sub in x 13(6) - 2y = 70 78 - 2y = 70 y=4 Yep, this is the exact same as simultaneous equations
x - 2y = -4 2x - y = 1 To solve this system of equations, I used matrices, and got x = 2 and y = 3.
If: 12 = 2y+x then y = -1/2x+6 So: y = 2x+4 and y = -1/2x+6 which means that they are perpendicular lines
(4, -1)
x= 3 and y = 2
16x - 2y = 74 (Eq 1) 2x - 2y = 4 (Eq 2) from Eq 2, 2y = 2x - 4 Substitute in Eq 1 16x - (2x - 4) =74 ie 16x - 2x + 4 = 74 ie 14x = 70 ie x = 5 2y = 2x - 4 = 10 - 4 = 6 y =3 Check 16 x 5 - 2 x 3 = 80 - 6 = 84 QED
-2x + 2y = 4 is equivalent to twice -2 + y = 2 which is the equation of a straight line.
-2X + 2Y = 4 2Y = 2X + 4 Y = X +2 by inspection, 2 but, you could also 0 out X in original equation -2(0) + 2Y = 4 2Y = 4 Y = 2
The equation "x plus 2y equals 5" is: x + 2y = 5 2y = 5 - x y = 5/2 - 1/2x y = -1/2x + 5/2
It doesn't look like you have anything that can be determined. The most confusing part of this is the -2x 2y = -4
The ordered pair is (3, 2).
The ordered pair is (2, 3).
1 solution