The question contains an expression. An expression does not have an answer - it cannot be solved.
x3 + 125 Use the sum of two cubes. (x+5)(x2-5x+25)
(x - 5)(x^2 + 5x + 25)
If 'x' is greater than ' 1 ', then it's 5x .If 'x' is less than ' 1 ', then it's 5 .
x+4x+5=5x+5
The question contains an expression. An expression does not have an answer - it cannot be solved.
(x+5)(x^2-5x+25)
x(x2+5x+6)
5x^2(4x - 5)(5x + 11)
x3 + 125 Use the sum of two cubes. (x+5)(x2-5x+25)
x(x + 2)(x + 3) x = 0, -2, -3
x+4x+5 = 0 5x + 5 = 0 5x = -5 x = -1
5(x2 + x + 1)
It is an algebraic expression that can be simplified to: 11x+5
(x - 5)(x^2 + 5x + 25)
5x cubed
x=6