7x2- 63 = -35, when x equals 2
x = 20
12
The answer is 144. The compound operator for (a) and (b) in each pair is a * (a+b). For 9 and 7, this is 9 x (9+7) = 9 x 16 = 144.
2+3 = 5 * 2 = 10. 7+2 = 9 * 7 = 63.6+5 = 11 * 6 = 66.x+y = z * x = n.9+7 = 16 * 9 = 144
2 squared plus 2 x 3 = 10, 7 squared plus 7 x 2 = 63, 6 squared plus 6 x 5 = 66,8 squared plus 8 x 4 = 96 so 9 squared plus 9 x 7 = 81 + 63 = 144.
9 plus 7 equals 144. Generally, x plus y = x(x+y).
7x2- 63 = -35, when x equals 2
x = 20
12
The answer is 144. The compound operator for (a) and (b) in each pair is a * (a+b). For 9 and 7, this is 9 x (9+7) = 9 x 16 = 144.
X = √63
2+3 = 5 * 2 = 10. 7+2 = 9 * 7 = 63.6+5 = 11 * 6 = 66.x+y = z * x = n.9+7 = 16 * 9 = 144
In reverse: 63 - 1 = 2n = 62 62 / 2 = 31 Now as the question: (2 x 31) + 1 = 62 + 1 = 63 Q.E.D.
63 times 2 equals 126.
14. the way i do it is 2/9 x 63/1 is actually the same as 63/9 x 2/1 which equals 7 x 2.
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