2x+2=x+6 first subtract 2x. -2x -2x2=-1x+6 then subtract 6-6 -6-4=-1x finally divide by -1x=4 X equals four.
5 - 2x = 8 x = -1 and 1/2 4x = 6 x = 6/4 or 3/2
(4 + 2x) - (-2x + 1) = 13 + 6 4 + 2x + 2x -1 = 19 4x +3 = 19 4x = 19 - 3 4x = 16 therefore x = 16/4 x = 4
x = 2y = 4
y=x+5
2x + 4 = 10 2x = 10 - 4 = 6 2x = 6 x = 6/2 = 3
2x+2=x+6 first subtract 2x. -2x -2x2=-1x+6 then subtract 6-6 -6-4=-1x finally divide by -1x=4 X equals four.
5 - 2x = 8 x = -1 and 1/2 4x = 6 x = 6/4 or 3/2
This is not Calculus. 6 + (2*4 = 8) = 14.
4+2x-2x+1=13+6 Combine like terms. (4+1=5; 2x-2x=0; 13+6=19) 5=19 This problem has no solution.
2x+4 = -16 2x = -16-4 2x = -20 x = -10
x=4
(4 + 2x) - (-2x + 1) = 13 + 6 4 + 2x + 2x -1 = 19 4x +3 = 19 4x = 19 - 3 4x = 16 therefore x = 16/4 x = 4
x=1
x = 2y = 4
If: 12 = 2y+x then y = -1/2x+6 So: y = 2x+4 and y = -1/2x+6 which means that they are perpendicular lines
-2(5x+3)-2x<-3(2x-4)+2