Solve this simultaneous equation by the elimination method:
x+y = 12
x-y = 4
Add both equations together:
2x = 16
Divide both sides by 2 to find the value of x:
x = 8
Substitute the value of x into the original equations to find the value of y:
Therefore: x = 8 and y = 4
If the x=4, then its equivelent to 12 + 4, which equals 16.
4 x 2 + 4 = 12 x = 4
x = 12
x = -4 and y = 4
6x+4 = x+12+4x-6 6x-x-4x = 12-6-4 x = 2
If the x=4, then its equivelent to 12 + 4, which equals 16.
4 x 2 + 4 = 12 x = 4
x = 12
x = -8
16
x = -4 and y = 4
2+x-4 = 12 x = 12+4-2 x = 14
x=12 because 12 over 6 is 2,and 2 plus 4 is 6.
6x+4 = x+12+4x-6 6x-x-4x = 12-6-4 x = 2
x2+4=12 x=4 or another way to ask that is 2x+4=12 x=4 because then you do 2 times 4 then + 4 it equals to 12
x = 4
In 6x + 4 = 12, x = 4/3