are you talking about a system of equations where x+3y=-7 -x+2y=-8 if so, then the answer is {2,-3}
(3, 2)
-2y=x+8 is the answer
Therefore, y = 4 7 + 2y = 15 7-7 + 2y = 15-7 Subtract 7 from both sides 2y = 8 Divide by 2 to get y alone 2y/2 = 8/2 y = 4
3x+2y=20 5x-2y=1 (3x+2y) + (5x-2y)= 20+1 3x+5x= 21....... 8x=21.........x=2 5/8 Subsitute x=3(2 5/8)+ 2y=20........... 7 7/8 +2y=20.........2y= 20- 7 7/8....... y=6 1/16
are you talking about a system of equations where x+3y=-7 -x+2y=-8 if so, then the answer is {2,-3}
Sum Numb!
(3, 2)
x = 11/7 and y = 12/7
-2y=x+8 is the answer
Therefore, y = 4 7 + 2y = 15 7-7 + 2y = 15-7 Subtract 7 from both sides 2y = 8 Divide by 2 to get y alone 2y/2 = 8/2 y = 4
3x+2y=20 5x-2y=1 (3x+2y) + (5x-2y)= 20+1 3x+5x= 21....... 8x=21.........x=2 5/8 Subsitute x=3(2 5/8)+ 2y=20........... 7 7/8 +2y=20.........2y= 20- 7 7/8....... y=6 1/16
x = 3 and y = 5
x = 7 - 2y 3x = 21 - 6y 21 - 6y + 2y = 5 21 - 4y = 5 21 - 16 = 5 4y = 16 y = 4 x + 8 = 7 x = -1 Check it. -3 + 8 = 5 -1 + 8 = 7 It checks.
Add the two equations: x + y - x + 2y = 8 + 7 ie 3y = 15 so y = 5 making x = 3.
3x + 2y = 5x + 2y = 7Subtract (2) from (1) to give: 3x - x + 2y - 2y = 5 - 7→ 2x = -2→ x = -1Substitute for x in (1)3(-1) + 2y = 5→ -3 + 2y = 5→ 2y = 8→ y = 4Substitute for x and y in (2) to check answer:x + 2y = -1 +2(4) = -1 + 8 = 7 as required. Thus:x = -1y = 4
x + 2y = 7 So x = 7 - 2y Substitute this value for x in the second equation which then is: 2(7 - 2y) + y = 8 Simplify: 14 - 4y + y = 8 -3y = -6 y = 2 Put this value of y back into the first equation: x + 2*2 = 7 ie x + 4 = 7 x = 3