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1 is not correct.
The correct solution is x = -1 or -6.
You can easily find it this way:
Factorising, we obtain
x2 + 7x + 6 = (x + 1)(x + 6) = 0.
The above is true if, and only if, either,
x + 1 = 0, or, else,
x + 6 = 0; that is, if
x = -1 or -6, which is the answer we sought.
The rule is that two numbers multiply to give a product of zero, if, and only if, one of the two numbers is zero.
To check our answer, let's try substitution into the original equation:
Does (-1)2 + 7(-1) + 6 = 0?
We see that 1 - 7 + 6 = 0.
Does (-6)2 + 7(-6) + 6 = 0?
We see that 36 - 42 + 6 = 0.
The answer is yes, both times, thus assuring us that we have found the correct answer.
63828
No, It's a a quadratic equation because you have X squared.
x2 - 7x + 6 = 0(x - 6)(x - 1) = 0x = 6, x = 1
If you mean 5x^2 -7x +2 = 0 then it is a quadratic equation with solutions of x = 2/5 or x = 1
http://authors.library.caltech.edu/25030/7/05_Calc1_Chapter2w.pdf visit.
63828
No, It's a a quadratic equation because you have X squared.
x2 - 7x + 6 = 0(x - 6)(x - 1) = 0x = 6, x = 1
49/4 or 12.25
5x2+7x = 12 5x2+7x-12 = 0 (5x+12)(x-1) = 0 x = -12/5 or x = 1
x^2 - 7x = 0 x(x - 7) = 0 x = 0 or x - 7 = 0 x = 0 or x = 7
If you mean 5x^2 -7x +2 = 0 then it is a quadratic equation with solutions of x = 2/5 or x = 1
http://authors.library.caltech.edu/25030/7/05_Calc1_Chapter2w.pdf visit.
x2 +7x = 30 x2 +7x - 30 = 0 (x + 10)(x - 3) = 0 Now: x + 10 = 0 or x - 3 = 0 So: x = -10 or x = 3
x2 + 7x = 2x2 + 6 x2 - 2x2 + 7x = 6 -x2 +7x - 6 = 0 or alternatively x2 - 7x + 6 = 0
x2+7x+12=0 x2+7x=-12 x+Sqaure Root of 7x= 2(SQ Root Symbol)3
7x + 2 = 6x + 2 if and only x = 0.