Say x is 5 so 5 + 5 = 10 where as 5 times 5 = 25 The difference is "x + x" is a addition and "xx" (x times x) is a multiplication.
3 = 5+x-14 = 5 + x-1 = xx = -1
x=5 so it's 55+55= 110
no, because xx=x squared, and x squared is not linear
The idea is to simply replace x by its assumed value, 5. x + 6 = 5 + 6 = 11The idea is to simply replace x by its assumed value, 5. x + 6 = 5 + 6 = 11The idea is to simply replace x by its assumed value, 5. x + 6 = 5 + 6 = 11The idea is to simply replace x by its assumed value, 5. x + 6 = 5 + 6 = 11
Say x is 5 so 5 + 5 = 10 where as 5 times 5 = 25 The difference is "x + x" is a addition and "xx" (x times x) is a multiplication.
4
3 = 5+x-14 = 5 + x-1 = xx = -1
x=5 so it's 55+55= 110
no, because xx=x squared, and x squared is not linear
X3 + 10X2 + 25Xfactor out an XX(X2 + 10X + 25)factor inside parenthesesX(X + 5)(X + 5)X(X + 5)2=======X = 0X = - 5
if x2 = 5 the value of x has to be 5 divided by 2 which is 2.5 x = 2.5
The idea is to simply replace x by its assumed value, 5. x + 6 = 5 + 6 = 11The idea is to simply replace x by its assumed value, 5. x + 6 = 5 + 6 = 11The idea is to simply replace x by its assumed value, 5. x + 6 = 5 + 6 = 11The idea is to simply replace x by its assumed value, 5. x + 6 = 5 + 6 = 11
In C: x = 5 always means assign the value of 5 to x; x == 5 always means compare the value of x with 5.
If: 5-3x = x+1 then the value of x = 1
5 minus x is completely dependent on what the value of x is.
X = 5