If Y=10 when X=5 then when Y=20 (10 * 2) X must equal 10 (5 * 2). One must multiply the values on both sides of the equal sign by the same value to maintain their equality. In this case, since Y went from 10 to 20 it was multiplied by 2. That means we have to multiply the other side by 2 to maintain equivalence.
5x5=25. 5, 10, 15 , 20, 25.
(10-20) + (10-5) = -10 + 5 = 5 - 10 (because the order doesn't matter as long as the signs are correct) = -5
40/10 = 20/a 4= 20/a 20/4 = a a= 5
1/5, 2/10, 20%
5*20/10 = 100/10 = 10
20/2=10/2=5 5*2*2 equals prime factorization of 20.
2x - 5 = 15 2x = 20 x = 10
5x6 = 30 -10 = 20.
5x5=25. 5, 10, 15 , 20, 25.
(10-20) + (10-5) = -10 + 5 = 5 - 10 (because the order doesn't matter as long as the signs are correct) = -5
20 = 400
You can conclude that 3 out of 5 and 12 out of 20 are equivalent.
40/10 = 20/a 4= 20/a 20/4 = a a= 5
There are infinite possible solutions: For example: 5/20 + 5/20 = 10/20 3/20 + 7/20 = 10/20
1/5, 2/10, 20%
5 times 20 equals 100
20 mL = 20*10-6 kL = 2*10-5 kL