-2
x2 + 3x + 7 = 5 ∴ x2 + 3x + 2 = 0 ∴ (x + 1)(x + 2) = 0 ∴ x ∈ {-2, -1}
-3/2
3x-1 = 11 3x = 11+1 3x = 12 x = 4 Therefore: x2+2 = 18
x3+3x2+3x+2 divided by x+2 equals x2+x+1
x = 2
-2
x2 + 3x + 7 = 5 ∴ x2 + 3x + 2 = 0 ∴ (x + 1)(x + 2) = 0 ∴ x ∈ {-2, -1}
1 and 2
-3/2
3x-1 = 11 3x = 11+1 3x = 12 x = 4 Therefore: x2+2 = 18
x3+3x2+3x+2 divided by x+2 equals x2+x+1
x2 - 3x + 2 = 0
x2 + 3x - 10 = (x + 5)(x - 2) ⇒ x = -5 or 2
x^2 + 3x + 7 = 6x + 18 x^2 - 3x - 11 = 0
Yes:- x2+3x+2 = 30 X2+3x+2-30 = 0 x2+3x-28 = 0 (x-4)(x+7) = 0 x = 4 or x = -7
- If 3X - 1 = 11, what is the value of X^2 + X?