y2 + x = 7 : this can be written as y2 = 7 - x or x = 7 - y2.
There is not a specific solution to this identity. For each different value assigned to x then a different value is generated for y. Or, it can be viewed that for each different value assigned to y then a different value is generated for x.
This expression is therefore a function.
Yes.
To determine if the equation ( x^2 + y^2 = 1 ) can be expressed as ( y ) as a function of ( x ), you can solve for ( y ). Rearranging gives ( y^2 = 1 - x^2 ), leading to ( y = \pm \sqrt{1 - x^2} ). Since there are two values of ( y ) (one positive and one negative) for most values of ( x ) in the interval ([-1, 1]), ( y ) cannot be expressed as a single-valued function of ( x ). Thus, the equation does not define ( y ) as a function of ( x ).
The vertex is at the point (0, 4).
Area of a circle equals pi (3.14) times the radius squared.
The number that equals 121 when squared is 11.
determine whether each relation is a function y equals -8
5
Yes.
To determine if the equation ( x^2 + y^2 = 1 ) can be expressed as ( y ) as a function of ( x ), you can solve for ( y ). Rearranging gives ( y^2 = 1 - x^2 ), leading to ( y = \pm \sqrt{1 - x^2} ). Since there are two values of ( y ) (one positive and one negative) for most values of ( x ) in the interval ([-1, 1]), ( y ) cannot be expressed as a single-valued function of ( x ). Thus, the equation does not define ( y ) as a function of ( x ).
The vertex is at the point (0, 4).
Area of a circle equals pi (3.14) times the radius squared.
The number that equals 121 when squared is 11.
5.477225575 squared equals 30.
8
b = sqrt32 or 4 root 2
No, it equals -2xy. lrn2math
4