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If you toss a fair coin 10 times and it lands on heads 8 times what is the probability that it will land on heads?
Since it is a fair coin, the probability is 0.5
What is the probability is of getting 3 heads in a row if I toss the coin 10 times?
The probability of getting 3 or more heads in a row, one or more times is 520/1024 = 0.508 Of these, the probability of getting exactly 3 heads in a row, exactly once is 244/1024 = 0.238
A coin is flip 8 times and the probability that the result have exactly have three heads?
It is 0.1042
Assuming the sequences are all equally likely what is the probability that you will get exactly two heads when you toss a coin three times?
To find the probability of getting exactly two heads when tossing a coin three times, we first determine the total number of possible outcomes, which is (2^3 = 8). The favorable outcomes for getting exactly two heads are: HHT, HTH, and THH, totaling 3 outcomes. Therefore, the probability of getting exactly two heads is ( \frac{3}{8} ).
What is the probability of getting exactly two heads with 4 coin tosses?
To find the probability of getting exactly two heads in four coin tosses, we can use the binomial probability formula. The number of ways to choose 2 heads from 4 tosses is given by the binomial coefficient ( \binom{4}{2} = 6 ). The probability of getting heads on each toss is ( \frac{1}{2} ), so the probability of getting exactly 2 heads is ( \binom{4}{2} \times \left(\frac{1}{2}\right)^2 \times \left(\frac{1}{2}\right)^2 = 6 \times \frac{1}{16} = \frac{6}{16} = \frac{3}{8} ). Thus, the probability of getting exactly two heads is ( \frac{3}{8} ).
If you toss a fair coin 10 times and it lands on heads 8 times what is the probability that it will land on heads?
Since it is a fair coin, the probability is 0.5
You toss a coin 5 times and it lands heads up each time what is the probability that it will lands heads the sixth toss?
1/2, or 50% since you are only asking what the probability of the last outcome is.
What is the probability is of getting 3 heads in a row if I toss the coin 10 times?
The probability of getting 3 or more heads in a row, one or more times is 520/1024 = 0.508 Of these, the probability of getting exactly 3 heads in a row, exactly once is 244/1024 = 0.238
If you were to flip a coin 4 times what is the probability it will land on heads the same number of times that it lands on tails?
50%
A coin is flip 8 times and the probability that the result have exactly have three heads?
It is 0.1042
If a coin is tossed 5 times what is the probability it will land on heads?
There is a 50% chance that it will land on heads each toss. You need to clarify the question: do you mean what is the probability that it will land on heads at least once, exactly once, all five times?
A fair coin is flipped three times what is the probability that the coin lands heads each time?
7/8
Assuming the sequences are all equally likely what is the probability that you will get exactly two heads when you toss a coin three times?
To find the probability of getting exactly two heads when tossing a coin three times, we first determine the total number of possible outcomes, which is (2^3 = 8). The favorable outcomes for getting exactly two heads are: HHT, HTH, and THH, totaling 3 outcomes. Therefore, the probability of getting exactly two heads is ( \frac{3}{8} ).
If a coin is tossed 8 times what is the probability that it land on heads exactly four times?
If p is the probability that any one toss lands on "heads", the probability that exactly 4 toss out of 8 lands on head is this: p^4 * (1-p)^4 * C(4,8) Where C(k,n) is an old notation for n! / ( k! * (n-k)! ) So C(4,8) = 8! / ( 4! * 4!) = 8*7*6*5 / 24 = 70 If your coin is well balanced, p is 50% and you get your answer: (0.5)^8 * 70 = 70/256 =~ 27,34%
What is the probability that exactly two times head are being tossed?
The answer depends on how many times the coin is tossed. The probability is zero if the coin is tossed only once! Making some assumptions and rewording your question as "If I toss a fair coin twice, what is the probability it comes up heads both times" then the probability of it being heads on any given toss is 0.5, and the probability of it being heads on both tosses is 0.5 x 0.5 = 0.25. If you toss it three times and want to know what the probability of it being heads exactly twice is, then the calculation is more complicated, but it comes out to 0.375.
What is the probability of getting exactly two heads with 4 coin tosses?
To find the probability of getting exactly two heads in four coin tosses, we can use the binomial probability formula. The number of ways to choose 2 heads from 4 tosses is given by the binomial coefficient ( \binom{4}{2} = 6 ). The probability of getting heads on each toss is ( \frac{1}{2} ), so the probability of getting exactly 2 heads is ( \binom{4}{2} \times \left(\frac{1}{2}\right)^2 \times \left(\frac{1}{2}\right)^2 = 6 \times \frac{1}{16} = \frac{6}{16} = \frac{3}{8} ). Thus, the probability of getting exactly two heads is ( \frac{3}{8} ).
When a fair coin is tossed twenty times in a row what is the probability that you get exactly fifteen heads?
3/8ths
