You have rolled doubles so the full set of possible outcomes is [1,1], [2,2], [3,3], [4,4],[5,5] and [6,6] - that is six in all.
Of these the first four are favourable outcomes (sum < 9)
So the required probability is 4/6 or 2/3
It is 1/6.
The probability is 8/36 or 2/9
The probability is 1, if the dice are rolled often enough.
Probability is desired options over total options. There are 6 faces on a standard dice, so NOT rolling a 5 is 5/6.
The probability is 1, if the dice are rolled often enough.
If they are normal dice, the probability is 0.
It is 1/6.
The probability is 8/36 or 2/9
The probability is 1, if the dice are rolled often enough.
Probability is desired options over total options. There are 6 faces on a standard dice, so NOT rolling a 5 is 5/6.
The probability is 1, if the dice are rolled often enough.
If you rolled 2 fair dice, the probability of having a sum of 6 is 5 over 36
If the dice are fair then it is 5/36.
It is 1/9.
7
The probability of rolling 12 with 2 dice is 1 in 36. The probability of not rolling 12 with 2 dice is 35 in 36.
Assuming these are regular dice, the probability is 1.