You have rolled doubles so the full set of possible outcomes is [1,1], [2,2], [3,3], [4,4],[5,5] and [6,6] - that is six in all.
Of these the first four are favourable outcomes (sum < 9)
So the required probability is 4/6 or 2/3
It is 1/6.
The probability is 8/36 or 2/9
The probability is 1, if the dice are rolled often enough.
Probability is desired options over total options. There are 6 faces on a standard dice, so NOT rolling a 5 is 5/6.
The probability is 1, if the dice are rolled often enough.
If they are normal dice, the probability is 0.
It is 1/6.
The probability is 8/36 or 2/9
The probability is 1, if the dice are rolled often enough.
Probability is desired options over total options. There are 6 faces on a standard dice, so NOT rolling a 5 is 5/6.
The probability is 1, if the dice are rolled often enough.
If you rolled 2 fair dice, the probability of having a sum of 6 is 5 over 36
If the dice are fair then it is 5/36.
It is 1/9.
If two fair dice were rolled, there would be 36 outcomes. (1,1),(1,2),....,(6,6) The maximum sum would be 12. Therefore, the probability that the total number of spots shown is equal to 15 is zero.
The probability of rolling 12 with 2 dice is 1 in 36. The probability of not rolling 12 with 2 dice is 35 in 36.
7