Q: Z2 plus 9z plus 18

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(2-r)e-rr

a2+b2+c2=x2+y2+z2 divide each side by 2 (a2+b2+c2)/2=(x2+y2+z2)/2 a+b+c=x+y+z

There appear to be 10 terms in the determinant. A determinant can only have a perfect number of terms. So something has gone wrong with the question. 1: x2 plus 1 2: xy 3: xz 4: xy 5: y2 plus 1 6: yz 7: 1 plus x2 plus y2 plus z2 8: xz 9: yz 10: z2 plus 1

(z - 6)(z - 6)

z2 - 12 + 36 is the same as z2 + 24. That's a simplification, but not a solution. There's nothing to solve, because the question doesn't give an equation. If z2+24 were equal to something, then we'd have an equation, and we would be thrilled to solve it for the value of 'z'.

Related questions

its either (z2+ 9)(z - 2) , (z2+ 2)(z - 9) , or (z2- 9)(z - 2)

z2

(2-r)e-rr

a2+b2+c2=x2+y2+z2 divide each side by 2 (a2+b2+c2)/2=(x2+y2+z2)/2 a+b+c=x+y+z

0

There appear to be 10 terms in the determinant. A determinant can only have a perfect number of terms. So something has gone wrong with the question. 1: x2 plus 1 2: xy 3: xz 4: xy 5: y2 plus 1 6: yz 7: 1 plus x2 plus y2 plus z2 8: xz 9: yz 10: z2 plus 1

(z - 6)(z - 6)

z2 - 12 + 36 is the same as z2 + 24. That's a simplification, but not a solution. There's nothing to solve, because the question doesn't give an equation. If z2+24 were equal to something, then we'd have an equation, and we would be thrilled to solve it for the value of 'z'.

If you mean how do you factor z2 + 50z + 49, since the coefficient of z2 is 1, you just have to figure out what two numbers when multiplied together give you 49 and when added together give you 50. That's obviously 49 and 1. So... z2 + 50z + 49 = (z + 49)(z + 1)

Expand z plus 11 times z plus 11 = (z+11)(z+11) = z2 + 22z + 121.

3z2 + 45z + 42 = 3(z2 + 15z + 14) = 3(z + 1)(z + 14).

2z+6z+24=0 8z+24=0 8z= -24 z= - 3