It is not clear what you mean by "oppisites" or even opposite. Often a number is the opposite of its opposite. So if the first is greater than the second, the second, which is the opposite of the first, is smaller than the first.
The difference depends on the integers. If the first integer is greater than the second then difference is positive. If the first integer is less than the second then difference is negative. For example 6-4 = +2; 4-6 = -2
Since the integer part is equal, just compare the first digit after the decimal point. (If the first digit should happen to be the same, compare the second digit, etc.)
The first integer must equal 77 - 69 = 8 , since doubling it increases the sum by this amount. Similarly, the second integer must = 91 - 69 = 22. Then the third integer is 69 - 22 - 8 = 39.
Any integer greater than one can be co-prime.
It is not clear what you mean by "oppisites" or even opposite. Often a number is the opposite of its opposite. So if the first is greater than the second, the second, which is the opposite of the first, is smaller than the first.
The difference depends on the integers. If the first integer is greater than the second then difference is positive. If the first integer is less than the second then difference is negative. For example 6-4 = +2; 4-6 = -2
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powpublic static double pow(double a, double b) Returns the value of the first argument raised to the power of the second argument. Special cases: If the second argument is positive or negative zero, then the result is 1.0.If the second argument is 1.0, then the result is the same as the first argument.If the second argument is NaN, then the result is NaN.If the first argument is NaN and the second argument is nonzero, then the result is NaN.If the absolute value of the first argument is greater than 1 and the second argument is positive infinity, orthe absolute value of the first argument is less than 1 and the second argument is negative infinity,then the result is positive infinity.If the absolute value of the first argument is greater than 1 and the second argument is negative infinity, orthe absolute value of the first argument is less than 1 and the second argument is positive infinity,then the result is positive zero.If the absolute value of the first argument equals 1 and the second argument is infinite, then the result is NaN.If the first argument is positive zero and the second argument is greater than zero, orthe first argument is positive infinity and the second argument is less than zero,then the result is positive zero.If the first argument is positive zero and the second argument is less than zero, orthe first argument is positive infinity and the second argument is greater than zero,then the result is positive infinity.If the first argument is negative zero and the second argument is greater than zero but not a finite odd integer, orthe first argument is negative infinity and the second argument is less than zero but not a finite odd integer,then the result is positive zero.If the first argument is negative zero and the second argument is a positive finite odd integer, orthe first argument is negative infinity and the second argument is a negative finite odd integer,then the result is negative zero.If the first argument is negative zero and the second argument is less than zero but not a finite odd integer, orthe first argument is negative infinity and the second argument is greater than zero but not a finite odd integer,then the result is positive infinity.If the first argument is negative zero and the second argument is a negative finite odd integer, orthe first argument is negative infinity and the second argument is a positive finite odd integer,then the result is negative infinity.If the first argument is finite and less than zero if the second argument is a finite even integer, the result is equal to the result of raising the absolute value of the first argument to the power of the second argumentif the second argument is a finite odd integer, the result is equal to the negative of the result of raising the absolute value of the first argument to the power of the second argumentif the second argument is finite and not an integer, then the result is NaN.If both arguments are integers, then the result is exactly equal to the mathematical result of raising the first argument to the power of the second argument if that result can in fact be represented exactly as a double value.(In the foregoing descriptions, a floating-point value is considered to be an integer if and only if it is finite and a fixed point of the method ceil or, equivalently, a fixed point of the method floor. A value is a fixed point of a one-argument method if and only if the result of applying the method to the value is equal to the value.)A result must be within 1 ulp of the correctly rounded result. Results must be semi-monotonic.Parameters:a - the base.b - the exponent.Returns:the value ab.Taken from the Java api.
The additive opposite of the additive opposite is the number itself. The multiplicative opposite of the multiplicative opposite is the number itself, unless the number was 0, in which case the first opposite is not defined.
Since the integer part is equal, just compare the first digit after the decimal point. (If the first digit should happen to be the same, compare the second digit, etc.)
The first integer must equal 77 - 69 = 8 , since doubling it increases the sum by this amount. Similarly, the second integer must = 91 - 69 = 22. Then the third integer is 69 - 22 - 8 = 39.
Any integer greater than one can be co-prime.
Since the integer part is the same, compare the FIRST DIGIT after the decimal point.
No, the first integer, 23, is half the second, 46.
-7.800000000000001
The second ionization energy for lithium is greater than the first because removing the second electron requires breaking a stronger bond due to the higher effective nuclear charge after the first electron is removed. This leads to a greater energy input to remove the second electron compared to the first.