That doesn't factor neatly. Applying the quadratic formula, we find two real solutions: (8 plus or minus the square root of 10) divided by 3 x = 3.720759220056127 x = 1.6125741132772067
For (x, y) = (0, 3) the first equation gives: 2*0 + 3 = -3 that is, +3 = -3 which is FALSE. So (0, 3) is not a solution.
Take out the common factor, 3: 3x + 6 = 3(x + 2).
4x2-4x-3=0 can be written as (2x-3)(2x+1)=0 Anything times by 0 equals 0 ( the zero property of multiplication) therefore we need to make each one of these terms in brackets equal to 0. so 2x-3=0 giving x=3/2 and 2x+1=0 giving x=-1/2
9x(x2+3x-10) * * * * * 9x3 + 27x2 - 90x = 9x(x2 + 3x - 10) = 9x(x + 5)(x - 2).
2x+3=9x 3=9x-2x 3=7x x=3/7
2x+3=9x-2x -2x3=7x/7 /73/7=x
2x + 3 = 9x Subtract 2x from both sides: 3 = 7x Divide both sides by 7: 3/7 = x
X= -2
2x+5=11 2x=6 x=3
2x + 3 = 9x start by bringing the 2x over- minus it from both sides 3 = 7x divide 7 by on sides x= 3/7 x = .4285714285714 repeating.
2x + 3 = 9x start by bringing the 2x over- minus it from both sides 3 = 7x divide 7 by on sides x= 3/7 x = .4285714285714 repeating. :)
2x + 3y = 9x = 3, y = 1 therefore 6 + 3 = 9
2x + 6 + 9x = 39 11x + 6 = 39 11x = 39 - 6 11x = 33 x = 3
2x+3=9 2x=9-3 2x=6 2x/2=6/2 X=3
6x2 + 9x = 0 3x(2x + 3) = 0 3x = 0 or 2x + 3 = 0 x = 0 or x = -3/2
2x+7x-10=4x+3-2x 9x-10=2x+3 7x=13 x=13/7ans