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That doesn't factor neatly. Applying the quadratic formula, we find two real solutions: (8 plus or minus the square root of 10) divided by 3 x = 3.720759220056127 x = 1.6125741132772067
For (x, y) = (0, 3) the first equation gives: 2*0 + 3 = -3 that is, +3 = -3 which is FALSE. So (0, 3) is not a solution.
Take out the common factor, 3: 3x + 6 = 3(x + 2).
4x2-4x-3=0 can be written as (2x-3)(2x+1)=0 Anything times by 0 equals 0 ( the zero property of multiplication) therefore we need to make each one of these terms in brackets equal to 0. so 2x-3=0 giving x=3/2 and 2x+1=0 giving x=-1/2
9x(x2+3x-10) * * * * * 9x3 + 27x2 - 90x = 9x(x2 + 3x - 10) = 9x(x + 5)(x - 2).