W=P*t=(U*I)*t=(R*I)*I*t=R*I^2*t
=> here with I=4.5 A, R=3.5 Ohms, t=5.5 mins * 60 s/min = 330s
W= (3.5 * 4.5 * 4.5 * 330) J = 23388.75 J
The rest is dissipated as heat.
Most linear regulators absorb the amount of energy equal to (Vin-Vout)*I where Vin is the voltage into the regulator, Vout is the regulated output voltage, and I is the current flowing through the regulator. This energy is dissipated as heat. As to much heat will burn the device out, a heatsink is needed where the die of the device cannot adequately dissipate the waste heat into the atmosphere.
the current(1.1.11) atomic energy commission chairman is Dr.S.banerjee.
The reason for increasing the voltage in the electric network is, in fact, that it saves energy. The power dissipated in electric wiring is proportional to the square of the electric current. By increasing the voltage, the current decreases provided that the power consumption at the consumer is to remain constant. This means less loss in the electric network. For the same reason, very high voltages, hundreds of thousand volts, are used in long-distance wires. The voltage is converted using transformers when it reaches the consumers, with a relatively low power loss.
Current stops going into a capacitor when it's voltage is equal to the supply voltage. From then there is no flow of current, so there is no magnetic field. Yet the capacitor remains charged and has energy to release if required.
Kinetic Energy is energy that is dissipated in a crash.
Dissipated energy is the energy that is spread into the environment or lost
P = I2R (power = current squared times resistance). Therefore, if the current doubles, the amount of dissipated electrical energy will increase by a factor of 4.P = I2R (power = current squared times resistance). Therefore, if the current doubles, the amount of dissipated electrical energy will increase by a factor of 4.P = I2R (power = current squared times resistance). Therefore, if the current doubles, the amount of dissipated electrical energy will increase by a factor of 4.P = I2R (power = current squared times resistance). Therefore, if the current doubles, the amount of dissipated electrical energy will increase by a factor of 4.
Kinetic Energy is energy that is dissipated in a crash.
It isn't QUITE as simple as that. The relevant formula is: (power dissipated) = (current squared) x (resistance)So, the amount of energy dissipated not only depends on the resistance, but also on the current (that's what is measured in amperes). For example, if there is no current, there will be no power dissipated. The formula is about POWER; to get ENERGY, which is what you asked for, you need to multiply power by time.
yes ,Q factor is ratio of energy stored to energy dissipated
One example of dissipated energy is when using a light bulb. This is when elctrical energy is converted to light and heat energy. However, the only useful energy here is light energy as light bulbs do not need heat to function. Therefore, when you touch a light bulb it is hot and this is the dissipated energy as it is wasted and not needed.The energy dissipated is heat. In any example of transferring energy there is always dissipated energy and other examples are when cars are used. The energy is converted to kinetic energy but is also converted to sound energy which, in this example, is the dissipated enrgy.
the dissipated energy is lost as heat, as well as it is dissipated to do the work against frictional forces.
The power dissipated by a resistance ' R ' carrying a current ' I ' is [ I2R ].I2R = (4.5)2 x (3.5) watts = 70.875 joules per second5.5 minutes = (5.5 x 60) = 330 secondsEnergy = (power) x (time) = (70.875) x (330) = 23,388.75 joules
in form of heat energy
Heat
usually dissipated as heat.