Are all the factors of 97?

Answer 1

Just look how 97 factorial is calculated; there you already have a lot of factors. If you want, you can then split it up further, into prime factors:

97!

= 1 x 2 x 3 x 4 x 5 x 6 x 7 x 8 x 9 x 10 x ... x 97

= 1 x 2 x 3 x (2 x 2) x 5 x (2 x 3) x 7 x (2 x 2 x 2) x (3 x 3) x (2 x 5) ...

You can then combine the prime factors and express them as powers. If you want ALL the factors, and not just the prime factors, you need to find all combinations of each of the prime factors. For example, the 97 will appear once as a factor; you must try all combinations where this number appears once, and where it doesn't appear. Similarly, the number 43 will appear twice as a factor (for 43, and for 86 = 2 x 43), so you have to try all combinations where 43 doesn't appear at all, where it appears once, and where it appears twice. Note that the number of factors will be huge.

Answer 2

97 is a Prime number so it's only factors would be 97 and 1

Answer 3

97 is prime. End of story. ■
97 is already prime; no factorization required.

Answer 4

the factor tree for 93 is 3,31
93

^

1 93

^ ^

1 1 1 93

^

3 31

^ ^

1 3 1 31

Factor rainbow of 91: 1,3,31,93

Answer 5

97 is a prime number so it's only factors are 1 and 97.

Answer 6

97 has only two factors because it is a prime number. They are 1 and itself.

Answer 7

97 is a prime so it is divisible by only 1 and 97.

Answer 8

92

46,2

23,2,2

Answer 9

97 is already prime; no tree.

Answer 10

Two of them.