1, 3, 17, 51.
1 and 3
Yes, because 3 divides evenly into 51 with no remainder.
1, 3, 17, 51.
5 + 1 = 6 which is divisible by 3, so 51 is divisible by 3. [3 x 17 = 51]
3 and 17 go into 51.
51 ÷ 17 = 3
1, 3, 17, 51.
3 and 17 are factors of 51
1, 3, 17, 51.
51 is a Prime number, so only 1 and 51 can go into it.
1, 3, 17, 51.
1, 3, 17 and 51
1 and 3
Yes 3 will go into 51 an exact number (17) of times with no remainder. In other words 3*17=51
The common factors of 6 and 51 are 1 and 3.
A train * * * * * or GCF(6, 51) = 3